Answer:
1a: f(x) = x³ -6x² +9x -4
1b: no breaks; the function is defined everywhere
2a: (-∞, 5]
2b: y = -3; y = -1
2c: x → -∞, y → -3; x → ∞, y → -1
Step-by-step explanation:
<h3>1A:</h3>
The factored form of f(x) is ...
f(x) = (x -4)(x -1)²
f(x) = (x -4)(x² -2x +1) = x³ -2x² +x -4x² +8x -4
f(x) = x³ -6x² +9x -4
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<h3>1B:</h3>
The function h(x) is defined for all values of x to be either f(x) or g(x). The function f(x) is a polynomial function, so has no breaks in its domain. The function g(x) is defined for all values of x, so has no breaks in its domain.
There are no breaks in the domain of h(x).
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<h3>2A:</h3>
See the attachment for a graph.
-∞ < y ≤ 5 . . . . range of f(x)
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<h3>2B:</h3>
The asymptote as x → -∞ is the asymptote of the exponential function. The exponential term has an asymptote of y=0, but shifting it down 3 units means the asymptote is 0 -3:
x → -∞, y → -3 . . . . asymptote is y = -3
The asymptote as x → ∞ is the asymptote of the rational expression. That is the ratio of the leading terms: -x²/x² = -1.
x → ∞, y → -1 . . . . asymptote is y = -1
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<h3>2C:</h3>
See part B.
Answer:
(5/2,-5)
Step-by-step explanation:
plug in zero for each of the variables to get the other one
2x-0=5
2x=5
x=5/2
2(0)-y=5
-y=5
y=-5
If you are asking if your work is good,thn yes,you are right
For this case we have the following number:
57
We can write this number in the form of a word.
Therefore, we are giving it a different name.
By writing the number in the form of a word we have:
57: fifty-seven
Answer:
An equivalent name for the number 57 is given by:
fifty seven
Answer:
4.9
Step-by-step explanation:
Tenths is the number directly after the "." so the 8 in 4.87 is the tenth. Rounding is quite easy, since 7 is bigger than 5 you add 1 to the 8 thus rounding the 4.87 to 4.9