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Katarina [22]
3 years ago
12

A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the

ball after 6.0 seconds?

Physics
2 answers:
leva [86]3 years ago
8 0
Used an app called Mephyso to do the calculation.

-Dominant- [34]3 years ago
8 0

Answer:

Final speed of the ball, v = 19.2 m/s

Explanation:

Given that,

Acceleration of the ball, a=3.2\ m/s^2

Initially, the ball is at rest, u = 0

Time, t = 6 s

We need to find the final speed of the ball. It can be calculated using first equation of motion as :

v = u + at

v=0+3.2\times 6

v = 19.2 m/s

So, the final speed of the ball is 19.2 m/s. Hence, this is the required solution.

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