Question

A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the ball after 6.0 seconds?

Answer 1

Used an app called Mephyso to do the calculation.

Answer 2

Answer:

Final speed of the ball, v = 19.2 m/s

Explanation:

Given that,

Acceleration of the ball, $a=3.2\ m/s^2$

Initially, the ball is at rest, u = 0

Time, t = 6 s

We need to find the final speed of the ball. It can be calculated using first equation of motion as :

v = u + at

$v=0+3.2\times 6$

v = 19.2 m/s

So, the final speed of the ball is 19.2 m/s. Hence, this is the required solution.