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Varvara68 [4.7K]

3 years ago

14

Interactive Solution 22.43 provides one model for solving this problem. The maximum strength of the earth's magnetic field is ab

out 6.9 x 10-5 T near the south magnetic pole. Suppose we want to utilize this field with a rotating coil to generate 54.1-Hz ac electricity. What is the minimum number of turns (area per turn = 0.024 m2) that the coil must have to produce an rms voltage of 170 V?

1 answer:

laila [671]3 years ago

5 0

Answer:

427097

Explanation:

V = Voltage = 170 V

B = Magnetic field = $6.9\times 10^{-5}\ T$

f = Frequency = 54.1 Hz

A = Area = $0.024\ m^2$

Number of turns is given by

$N=\dfrac{V\sqrt{2}}{BA2\pi f}\\\Rightarrow N=\dfrac{170\sqrt{2}}{6.9\times 10^{-5}\times 0.024\times 2\pi\times 54.1}\\\Rightarrow N=427096.933536\approx 427097\ turns$

Number of turns is 427097

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You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.540 kg. All of the ice melts,

lbvjy [14]

Answer:

The value is $T_c = 12 .1 ^oC$

Explanation:

From the question we are told that

The mass of the ice cube is $m_i = 7.50 *10^{-3} \ kg$

The temperature of the ice cube is $T_i = 0^o C$

The mass of the copper cube is $m_c = 0.540 \ kg$

The final temperature of both substance is $T_f = 0^oC$

Generally form the law of thermal energy conservation,

The heat lost by the copper cube = heat gained by the ice cube

Generally the heat lost by the copper cube is mathematically represented as

$Q = m_c * c_c * [T_c - T_f ]$

The specific heat of copper is $c_c = 385J/kg \cdot ^oC$

Generally the heat gained by the ice cube is mathematically represented as

$Q_1 = m_i * L$

Here L is the latent heat of fusion of the ice with value $L = 3.34 * 10^{5} J/kg$

So

$Q_1 = 7.50 *10^{-3} * 3.34 * 10^{5}$

=> $Q_1 = 2505 \ J$

So

$2505 = 0.540 * 385 * [T_c - 0 ]$

=> $T_c = 12 .1 ^oC$

4 0

2 years ago

A firefighting crew uses a water cannon that shoots water at 25.0 m/s at a fixed angle of 53.0° above the horizontal. The fire-f

zysi [14]

Answer:

8.8 m and 52.5 m

Explanation:

The vertical component and horizontal component of water velocity leaving the hose are

$v_v = vsin(\alpha) = 25sin(53^0) = 25*0.8 = 19.97 m/s$

$v_h = vcos(\alpha) = 25cos(53^0) = 25*0.6 = 15 m/s$

Neglect air resistance, vertically speaking, gravitational acceleration g = -9.8m/s2 is the only thing that affects water motion. We can find the time t that it takes to reach the blaze 10m above ground level

$s = v_vt + gt^2/2$

$10 = 19.97t - 9.8t^2/2$

$4.9t^2 - 19.97t + 10 = 0$

$t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$t= \frac{19.9658877511823\pm \sqrt{(-19.9658877511823)^2 - 4*(4.9)*(10)}}{2*(4.9)}$

$t= \frac{19.9658877511823\pm14.24}{9.8}$

t = 3.49 or t = 0.58

We have 2 solutions for t, one is 0.58 when it first reach the blaze during the 1st shoot up, the other is 3.49s when it falls down

t is also the times it takes to travel across horizontally. We can use this to compute the horizontal distance between the fire-fighters and the building

$s_1 = v_ht_1 = 15*0.58 = 8.8 m$

$s_2 = v_ht_2 = 15*3.49 = 52.5m$

8 0

2 years ago

How do the three types of boundary's work together to keep the Earth at equilibrium?

Maurinko [17]

There are three types: divergent, convergent, and transform boundaries. I hope this helps.

8 0

2 years ago

Read 2 more answers

Where can I find springs that are the same size as the ones in a mechanical pencil

Fittoniya [83]

Answer:

Staples, Bestbuy, Maybe Homedepot

Explanation:

5 0

2 years ago

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If you were trying to describe the difference between power and work you could say...?

Paha777 [63]

Answer:

Look to the explanation

Explanation:

<u><em>Work done</em></u> is is the energy transferred to or from an object by means

of a force acting on the object.

Work is positive if energy transferred to the object, and work is

negative if energy transferred from the object.

<em>Work = Force in the direction motion of object × its displacement</em>

$W=F*s$

The SI unit of the work is joule (J)

<u><em>Power</em></u> is the rate of work

<em>Power = work done ÷ time taken</em>

Power = $\frac{F*s}{t}$

Displacement (s) ÷ time (t) = velocity (v)

<em>Power = Force × velocity</em>

$P=F*v$

The SI unit of the power is watt (w)

6 0

2 years ago