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Varvara68 [4.7K]
4 years ago
14

Interactive Solution 22.43 provides one model for solving this problem. The maximum strength of the earth's magnetic field is ab

out 6.9 x 10-5 T near the south magnetic pole. Suppose we want to utilize this field with a rotating coil to generate 54.1-Hz ac electricity. What is the minimum number of turns (area per turn = 0.024 m2) that the coil must have to produce an rms voltage of 170 V?
Physics
1 answer:
laila [671]4 years ago
5 0

Answer:

427097

Explanation:

V = Voltage = 170 V

B = Magnetic field = 6.9\times 10^{-5}\ T

f = Frequency = 54.1 Hz

A = Area = 0.024\ m^2

Number of turns is given by

N=\dfrac{V\sqrt{2}}{BA2\pi f}\\\Rightarrow N=\dfrac{170\sqrt{2}}{6.9\times 10^{-5}\times 0.024\times 2\pi\times 54.1}\\\Rightarrow N=427096.933536\approx 427097\ turns

Number of turns is 427097

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The relationship between variables might be either directly porportional to each other or inversely proportional to each other. <em>For instance, the current flowing is _</em><em><u>directly</u></em><em>_ </em><em>proportional to the potential difference across</em> it.

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Since I do not have the graph, I will propose two potential options and I will describe each of them.

I suggest you to choose the one that matches the shape of graph 3.

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<em>The current flowing through this component is __</em><u><em>DIRECTLY</em></u><em>__ proportional to the potential difference across it</em>.

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In the attached files you will find graphs of both options.

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You can learn more about the Ohm's law at  

brainly.com/question/17286882?referrer=searchResults

You can learn more about the relationship between variables at

brainly.com/question/16937826?referrer=searchResults

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