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Diano4ka-milaya [45]
3 years ago
11

The gravitational force exerted by the Sun on the Earth is __________ the gravitational force exerted by the Earth on the Sun.

Physics
2 answers:
marishachu [46]3 years ago
7 0

Answer:

same as

Explanation:

According to Newton's 3rd law, the force that the Earth exert on the Sun would be equal (and in opposite direction) with the force that the Sun exerts on the Earth.

Also Newton's gravitational law states the formula for the attraction between objects with mass, is the same for both objects

fiasKO [112]3 years ago
5 0

Answer:

equal

Explanation:

Newton's law of universal gravitation states that "any two objects A and B exert a gravitational force of attraction on each other and the magnitude of this force is proportional to the product of the masses of the objects and inversely proportional to the square of the distance separating these objects".

This means that two objects interacting together will exert the same force of gravity (or simply gravitational force) on each other. Though the masses of the two objects may be different, the magnitude of the force that one object exerts on the other is still the product of these masses and the inverse of the square of the distance between them.

Therefore, the gravitational force that the Sun, though of higher mass than the Earth, will exert on the Earth is the same as that which the Earth will exert on the Sun.

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Depending on circumstances, there are times when divers may wish to be positively, negatively or neutrally buoyant. True. False.
ser-zykov [4K]

Answer:

True

Explanation:

Buoyancy is the most important factors for divers. All they do underwater is to observe the life down there but they also have some other work. However, divers may want to be negatively buoyant when they want to go on deep exploration. When they reach a destination, they may want to observe and neutral buoyancy then will be useful. When they want to go back on surface, they’ll utilize positive buoyancy.

7 0
3 years ago
A father pushes his child on a swing. He pushes with a force of 20 N or a distance of 1 m, with the force always maintained para
Firlakuza [10]

Answer:

20 Joules

Explanation:

Work is done whenever a force moves a body through a certain distance in the direction of the force. So, work done is the product of force and distance moved.

Therefore, we have;

Work done = Force x distance

i.e   Wd = Fs

Given that: F = 20 N and s = 1 m, then;

Wd = 20 N x 1 m

     = 20 Nm

The work done by the father is 20 Joules(Nm).

7 0
3 years ago
Please select the word from the list that best fits the definition
vagabundo [1.1K]

Answer:input work

Explanation:

7 0
2 years ago
Read 2 more answers
A river flowing steadily at a rate of 175 m3/s is considered for hydroelectric power generation. It is determined that a dam can
Alex_Xolod [135]

Answer:

137200000 watts or 137200 kilowatts

Explanation:

The formula for power is P= dhrg

Where P = Power in watts

d = density of water (1000 kg/m^3)

h = height in meters

r = flow rate in cubic meters per second,

g = acceleration due to gravity of 9.8 m/s^2,

Plugging in the known values,

we get

P = 1000 kg/m^3 * 80 m * 175 m^3/s * 9.8 m/s^2

P = 80000 kg/m^2 * 175 m^3/s * 9.8 m/s^2

P = 14000000 kg m/s * 9.8 m/s^2

P = 137200000 kg m^2/s^3

P = 137200000 watts or 137200 kilowatts

The above figure assumes 100% efficiency which is impossible. A good efficiency would be 90% so the actual power available would be close to 0.90 * 137200 = 123480 kilowatts

6 0
3 years ago
Consider a variety of colors of visible light (say 400 nm to 700 nm) falling onto a pair of slits.
babymother [125]

Answer:

Explanation:

The relationship between angle and wavelength for maxima and minima in Young's double slit experiment is given by

For constructive interference

d\sin \theta =m\lambda

For Destructive interference

d\sin \theta =(m+\frac{1}{2})\lambda

where \lambda =wavelength

d=slit\ width

m=order of maxima and minima

for second order maxima i.e. m=2

For smallest separation taking \lambda =400 nm, \theta =90^{\circ}

d\sin 90=2\times 400\times 10^{-9}

d=0.8\times 10^{-6}

d=0.8\mu m

   

6 0
3 years ago
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