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3 years ago

The gravitational force exerted by the Sun on the Earth is __________ the gravitational force exerted by the Earth on the Sun.

Physics

2 answers:

marishachu [46]3 years ago

7 0

Answer:

same as

Explanation:

According to Newton's 3rd law, the force that the Earth exert on the Sun would be equal (and in opposite direction) with the force that the Sun exerts on the Earth.

Also Newton's gravitational law states the formula for the attraction between objects with mass, is the same for both objects

fiasKO [112]3 years ago

5 0

Answer:

equal

Explanation:

Newton's law of universal gravitation states that "any two objects A and B exert a gravitational force of attraction on each other and the magnitude of this force is proportional to the product of the masses of the objects and inversely proportional to the square of the distance separating these objects".

This means that two objects interacting together will exert the same force of gravity (or simply gravitational force) on each other. Though the masses of the two objects may be different, the magnitude of the force that one object exerts on the other is still the product of these masses and the inverse of the square of the distance between them.

Therefore, the gravitational force that the Sun, though of higher mass than the Earth, will exert on the Earth is the same as that which the Earth will exert on the Sun.

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How can shorter string produce more fundamental frequency in two string of different length?

Nana76 [90]

Answer:

Shorter string produces more frequency in two different strings because the equation for frequency is velocity/wavelength , this means that a shorter string creates a shorter wavelength which essentially increases the total frequency produced

5 0

3 years ago

9. A constant velocity means acceleration is

vampirchik [111]

Answer:

d. zero

Explanation:

Constant velocity means the acceleration is zero. In this case the velocity does not change,

hope this helps you

have a good day :)

6 0

3 years ago

Two objects, m1 = 0.6 kg and m2 = 4.4 kg undergo a one-dimensional head-on collision

Sidana [21]

a) The velocity after the collision.is 11.456 m/s.

b) The kinetic energy lost due to the collision is 44.564 J.

<h3>What is conservation of momentum principle?</h3>

When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.

The external force is not acting here, so the initial momentum is equal to the final momentum. For inelastic collision, final velocity is the common velocity for both the bodies.

m₁u₁ +m₂u₂ =(m₁ +m₂) v

Given are the two objects, m1 = 0.6 kg and m2 = 4.4 kg undergo a one-dimensional head-on collision. Their initial velocities along the one-dimension path are vi1 = 32.4 m/s [right] and vi2 = 8.6 m/s [left].

(a) Substitute the values, then the final velocity will be

0.6 x32.4 +4.4 x 8.6 = (0.6+4.4)v

v = 11.456 m/s

Thus, the velocity after collision is 11.456 m/s.

(b) Kinetic energy lost due to collision will be the difference between the kinetic energy before and after collision.

= [1/2m₁u₁² +1/2m₂u₂² ] - [1/2(m₁ +m₂) v²]

Substitute the value, we have

= [1/2 x 0.6 x32.4² + 1/2 x4.4 x 8.6²] - [1/2 x(0.6+4.4)11.456²]

= 44.564 J

Thus, the kinetic energy lost due to the collision is 44.564 J.

Learn more about conservation of momentum principle

brainly.com/question/14033058

#SPJ2

4 0

2 years ago

Read 2 more answers

Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end to

Pie

Answer:

Vc = 2.41 v

Explanation:

voltage (v) = 16 v

find the voltage between the ends of the copper rods .

applying the voltage divider theorem

Vc = V x ( $\frac{Rc}{Rc + Ri}$ )

where

Rc = resistance of copper = $\frac{ρl}{a}$ (l = length , a = area, ρ = resistivity of copper)

Ri = resistance of iron = $\frac{ρ₀l}{a}$ (l = length , a = area, ρ₀ = resistivity of copper)

Vc = V x ( $\frac{\frac{ρl}{a}}{\frac{ρl}{a} + \frac{ρ₀l}{a}}$ )

Vc = V x ( $\frac{ρ x (\frac{l}{a})}{(ρ + ρ₀) x (\frac{l}{a})}$ )

Vc = V x ( $\frac{ρ}{ρ + ρ₀}$ )

where

ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter

ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter

Vc = 16 x ( $\frac{1.72 x 10^{-8}}{1.72 x 10^{-8} + 9.71 x 10^{-8}}$ )

Vc = 2.41 v

5 0

3 years ago

• what is the typical distance between two adjacent pins on a 14-pin dual-in-line ic package?

muminat

A 14 pin dual-in-line IC package[14 DIL] is an integrated socket which is most popular form of IC package and has a wide range of application in digital electronics.

The 14-pin DIL has two pairs per side and each pair contains seven connecting pins.

The pairs of pins are arranged linearly one after another.The typical dimensions of width is 6.5 mm and the typical dimension of length is 18 mm.

we are asked to calculate the typical distance between two adjacent pins.

The typical distance between two adjacent pins is calculated as-

$Typical\ distance =\frac{dimensional\ length}{number\ of\ pins\ in\ each\ row}$

$=\frac{18 mm}{7}$

$= 2.5714 mm$ [ans]

7 0

3 years ago