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3 years ago

Would the tide be higher when the moon is on the same side of earth as New Brunswick or on the opposite side why

Physics

1 answer:

Sindrei [870]3 years ago

3 0

Tide is the alternating pattern of rising and falling sea level with respect to land.

There are three types of tide relative to the position of the moon and sun to that of the earth.

1. Spring tides. Occur when the moon sun and earth arrange themselves more or less in a straight line, like an arrow. These tides are the highest and lowest tides.

2. Perigean spring tides. Occur when the new moon or full moon closely aligns with perigee, the closest point to the earth in the moon's orbit. These tides are not as high or low as the spring tides.

3. Neap tides. Occur when the sun and the moon are at right angles as seen from earth.The tides are at minimum range.

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An object moves at a constant speed of 6m/s. this means that the object

tiny-mole [99]

Answer:

An object moves at a constant speed of 6m/s. this means that the object moves 6 meters every second

Explanation:

5 0

4 years ago

A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00 m above the ground. At th

Elis [28]

Answer:

The water ballon that was thrown straight down at 2.00 m/s hits the ground first, 0.19 s before the other ballon.

Explanation:

The motions of the two water ballons are ruled by the kinematic equations:

$y=y_0+V_0t-gt^2/2$

We are only interested in the vertical motion, so that equation is all what you need.

1. Water ballon is thrown horizontally at sped 2.00 m/s.

The time the ballon takes to hit the ground is independent of the horizontal speed.

Since 2.00 m/s is a horizontal speed, you take the initial vertical speed equal to 0.

Then:

$y=y_0+V_0t-gt^2/2\\ \\ 0=6.00m-9.8\frac{m}{s^2} t^2/2\\ \\ t=\sqrt{2\times6.00m/9.8\frac{m}{s^2}}\\\\ t=1.11s$

2. Water ballon thrown straight down at 2.00 m/s

Now the initial vertical speed is 2.00 m/s down. So, the equation is:

$0=6.00m-2.00\frac{m}{s}t-9.8\frac{m}{s^2}t^2/2\\ \\ 4.9t^2+2t-6=0\\ \\ t=0.92s$

To solve the equation you can use the quadratic formula.

$t=\frac{-2+/-\sqrt{2^2-4(4.9)(-6)} }{2(4.9)}\\ \\ t=-1.33\\ \\ t=0.92$

You get two times. One of the times is negative, thus it does not have physical meaning.

3. Conclusion:

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

5 0

3 years ago

A horizontal clothesline is tied between 2 poles, 16 meters apart. When a mass of 3 kilograms is tied to the middle of the cloth

Alla [95]

Answer:

The magnitude of the tension on the ends of the clothesline is 41.85 N.

Explanation:

Given that,

Poles = 2

Distance = 16 m

Mass = 3 kg

Sags distance = 3 m

We need to calculate the angle made with vertical by mass

Using formula of angle

$\tan\theta=\dfrac{8}{3}$

$\thta=\tan^{-1}\dfrac{8}{3}$

$\theta=69.44^{\circ}$

We need to calculate the magnitude of the tension on the ends of the clothesline

Using formula of tension

$mg=2T\cos\theta$

Put the value into the formula

$3\times9.8=2T\times\cos69.44$

$T=\dfrac{3\times9.8}{2\times\cos69.44}$

$T=41.85\ N$

Hence, The magnitude of the tension on the ends of the clothesline is 41.85 N.

4 0

4 years ago

Read 2 more answers

A refrigerator had a mass of 73 kg. What is the weight of the refrigerator in newtons

Sophie [7]

Answer:

715.4 N

Explanation:

W = mg

= 73 kg*9.8m/s²

= 715.4 N

3 0

2 years ago

Read 2 more answers

A body of mass m, = 0.050 kg and initial velocity v₁ = 9 m / s turned to the right collides with a body of mass m₂ = 0.030 g wit

Andrej [43]

Answer:

1 m/s

Explanation:

Po = Pf

(0.050kg)(9 m/s) + (0.030kg)(v2) = (0.05kg + 0.030)(6 m/s)

0.45 kgm/s + (0.030kg)(v2) = 0.48 kgm/s

(0.030kg)(v2) = 0.03 kgm/s

v2 = 1 m/s

4 0

2 years ago