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Temka [501]
3 years ago
12

A ball is launched directly in the air at a speed of 40 feet per second from a platform located 10 feet in the air. The motion o

f the ball can be modeled using the function f(t)=−16t2+40t+10, where t is the time in seconds and f(t) is the height of the ball. When, in seconds, will the ball hit the ground? Write your answer to the nearest hundredth of a second. Do not include units in your answer.
Physics
1 answer:
crimeas [40]3 years ago
8 0

Answer:

The ball will hit the ground in 2.73 s

Explanation:

Hi there!

f(t) is the height of the ball at time "t". We need to find the value of "t" for which f(t) = 0.

f(t) = 0   Then:

-16 · t² + 40 · t + 10 = 0  

Solving the quadratic equation using the quadratic formula (a = -16, b = 40, c = 10):

t = -0.23 s and t = 2.72 s

Since time can´t be negative, be discard that value.

The ball will hit the ground in 2.73 s.

Have a nice day!

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Answer:

the pressure at B is 527psf

Explanation:

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ω = 20 /1.5

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6 0
3 years ago
1. The horizontal and vertical components of a projectile's velocity are
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The horizontal and vertical components of a projectile's velocity are independent of each other.

Answer: Option C

<u>Explanation:</u>

The path of a projectile is determined by two components of motion. They are termed as horizontal and the vertical components. Since both components velocity are perpendicular to each other, so it can stated that they are independent of each other.

Even it can seen that when the horizontal components of velocity is constant, then there will be change in the vertical components of velocity leading to free fall projectile path.

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5 0
3 years ago
Physics help please!
Oliga [24]

Answer:

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\dfrac{I_f}{I_i}=\dfrac{1}{3}

In this system the angular momentum is conserved

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Answer:

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