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Ber [7]
3 years ago
6

The set of points in a plane that are equidistant from a given point form a ____.

Physics
2 answers:
il63 [147K]3 years ago
8 0

Answer:

Circle

Explanation:

gtnhenbr [62]3 years ago
6 0
Circle

.......................
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A spacecraft has a momentum of 20,000 kg-m/s, and a mass of 250 kg. What is the magnitude of its velocity?
Harlamova29_29 [7]

Answer:

<h2>A. 80 m/s </h2>

Explanation:

The velocity of the spacecraft can be found by using the formula

v =  \frac{p}{m}  \\

p is the momentum

m is the mass

From the question we have

v =  \frac{20000}{250}  =  \frac{2000}{25}  \\

We have the final answer as

<h3>80 m/s</h3>

Hope this helps you

6 0
3 years ago
A truck travels to and from a stone quarry that is located 2.5 km to the east. What is the total distance traveled by the truck?
scoray [572]

Answer:

5 km

0

Explanation:

The question says the truck travelled to and fro from the stone quarry.

When going to the stone quarry, the distance was 2.5 km to the east.

On returning, the distance back is also 2.5km

Therefore total distance travelled is 2.5km + 2.5km

= 5km

The displacement 8s dependent on what is the initial and also the final position. The initial and the final position are one and the same thing. Because the truck starts and goes back to the same position, the displacement is zero.

5 0
3 years ago
Twoâ cars, 405 kilometersâ apart, begin driving toward each other on aâ long, straight highway. one car travels 70 kilometers pe
mart [117]
The space between the cars closes at (70+65)=135 km/hr. They collide in (405/135)=3 hours after they start moving. In 3 hours, the canary covers (100km/hr x 3)= 300 km.
8 0
4 years ago
cycling at 13.0 m/s on your new aero carbon fiber bike, how much times would it take a pro cyclist to ride in 120 km? Give your
sp2606 [1]

We have that the time in seconds, minutes, and hours is

t=1.083*10^{-4}s

T_{min}=1.805*10^{-6}min

T_{hours}=3.0083*10^{-8}hours

From the Question we are told that

Velocity v=13.0m/s

Distance d=120 km

Generally the equation for the Time  is mathematically given as

t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s

Therefore

T_{min}=1.083*10^{-4}s/60

T_{min}=1.805*10^{-6}min

And

T_{hours}=T_{min}/60

T_{hours}=3.0083*10^{-8}hours

For more information on this visit

brainly.com/question/12319416?referrer=searchResults

4 0
3 years ago
A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and
ad-work [718]
We can calculate the length of each spring by using the relationship:
F=kx
where
F is the force applied to the spring
k is the spring constant
x is the length of the spring (measured with respect to its rest position)

Re-arranging the equation, we have
x= \frac{F}{k}

The force applied to both spring is F=60 N. Spring A has spring constant of k=4 N/m, therefore its length with respect to its rest position is
x_A= \frac{F}{k_A}= \frac{60 N}{4 N/m}=15 m
Spring B has spring constant of k=5 N/m, so its length with respect to its rest position is
x_B= \frac{F}{k}= \frac{60 N}{5 N/m}=12 m

Therefore, the correct answer is
<span>D.Spring A is 3 m longer than spring B because 15 – 12 = 3.</span>
5 0
3 years ago
Read 2 more answers
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