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djverab [1.8K]
3 years ago
10

A honey bee flaps its wings 200 times per second. How much time is required for one wingbeat? Give your answer in milliseconds.

Physics
2 answers:
Schach [20]3 years ago
7 0

Answer:

The time is required for one wing beat is 5 millisecond.

Explanation:

Given that,

Frequency = 200 /sec

We need to calculate the time period

Using formula of time period

Time period is the reciprocal of the frequency.

T=\dfrac{1}{f}

T=\dfrac{1}{200}

T=0.005\ sec

T= 5\ miliseconds

Hence, The time is required for one wing beat is 5 millisecond.

kakasveta [241]3 years ago
3 0
A bees wings move so rapidly that studying them, even seeing them, has proved difficult.
The honeybees have a rapid wing beat honeybee flaps its wings 230 times every second.

Therefore, a bee flaps its wings over 200 times in about 1ms
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Question 33
pantera1 [17]

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A. The waves in the water travel faster and at a higher frequency than they travel on land.

Explanation:

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2 years ago
Question 2 (10 points)
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The force required to slow the truck was -5020 N

Explanation:

First of all, we find the acceleration of the truck, which is given by

a=\frac{v-u}{t}

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v = 11.5 m/s

u = 21.9 m/s

t = 2.88 s

So the acceleration is

a=\frac{11.5-21.9}{2.88}=-3.6 m/s^2

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Now we can find the force exerted on the truck, which is given by Newton's second law:

F=ma

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m = 1390 kg is the mass of the truck

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And substituting,

F=(1390)(-3.6)=-5004 N

So the closest answer among the option is -5020 N.

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

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