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KonstantinChe [14]
3 years ago
6

How would you use a number line to round 16800 to the nearest ten thousand?

Mathematics
1 answer:
allsm [11]3 years ago
4 0

Well you'd see if it's closer to 10000 or 20000.

In this case it would round to 20000.

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What is the measure of _C?
Pani-rosa [81]

Answer:

70°

Step-by-step explanation:

A+B+C=180°

70°+40°+C=180°

C=180°-110°

C=70°

4 0
3 years ago
Read 2 more answers
A car dealership increased the price of a certain car by 13%. The original price was $47400 what is the new price?
garik1379 [7]

Answer:

Step-by-step explanation:

To get the new price of the car multiply the original price by the percent increase in decimal form  +1. 11% in decimal form is 0.11 = 11/100. Add one to this and you get 1.11 = 1 + 0.11. So now multiply $49,800 * 1.11 = $55,278. If the problem had said they decreased the price by 11% you would use 1 - 0.11 = 0.89 because 89% is 11% less than 100%.

hope that helps my man

5 0
3 years ago
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Determine the measure of an angle (in radians) that cuts off an arc length of 6.4 inches in a circle with a 6.4 inch radius.
serg [7]
1 radian
because s= r × angle measurement in radian
we have s= arc , r = radian so we got the value
5 0
3 years ago
Easy question:
Delvig [45]

Answer:

3 hours and 45 minutes

Step-by-step explanation:

let's assume the tank has a volume of x liters.

let's assume the speed of filling it is x/6 liters per hour for A and x/10 liters per hour for B.

the formula to calculate the time is:

time = volume / speed

If the pumps work together, the total speed is x/6 + x/10, which is 16/60 x

So the time this takes is:

time = x / (16/60 x) = 60/16 hours = 3.75 hours = 3 hours and 45 minutes.

8 0
2 years ago
Find the equation of an exponential function in the form y = ab^x, given the points (0, 3) and (2, 108/25). Please simplify your
lilavasa [31]

We have the equation:

y=a\cdot b^x

We know two points and we will use them to calculate the parameters a and b.

The point (0,3) will let us know a, as b^0=1.

\begin{gathered} y=a\cdot b^x \\ 3=a\cdot b^0=a \\ a=3 \end{gathered}

Now, we use the point (2, 108/25) to calcualte b:

\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}

Then, we can write the equation as:

y=3\cdot(\frac{6}{5})^x

5 0
1 year ago
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