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Inessa [10]
3 years ago
9

What is the total number of electrons that can occupy the f sub level

Chemistry
2 answers:
Alisiya [41]3 years ago
7 0

<u>Answer:</u>

<em>14 electrons can occupy the f sub level</em>

<u>Explanation:</u>

Electronic configuration is the short representation which we use to represent the structure of an atom.

Atomic number of phosphorus is 15 so it has 15 electrons.

The electronic configuration of Phosphorus is given as 1s^2 2s^2 2p^6 3s^2 3p^3

Here the superscript number represents the electrons 2 + 2 + 6 + 2 + 3 = 15 electrons of Phosphorus

Orbital diagram too is used for this purpose.

A circle or a square is used to represent an orbital.

This is the orbital diagram of Radon (atomic number -86)  

Each orbital occupies 2 electron.

Shells are named using letters K, L, M, N and so on or using numbers 1, 2, 3, 4 etc.,

The number of electrons, a shell can accommodate is found using formula 2n^2 where n is the number of the shell.

Shell 1 contains subshell s

Shell 2 contains subshell s, p

Shell 3 contains subshell s, p, d

Shell 4 contains subshell s, p, d, f

Subshells or sub level are represented by letters s, p, d, f, g, h, i and so on.

s contains 1 orbital with 2 electrons

p subshell contains 3 orbital with 6 electrons

d with 5 orbitals and 10 electrons  

f with 7 orbitals and 14 electrons.

(Answer)

Zepler [3.9K]3 years ago
6 0

Answer:

14 Electrons

Explanation:

I know because I know

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3 years ago
Read 2 more answers
Learn how changes in binding free energy affect binding and the ratio of unbound and bound molecules.
Delvig [45]

C)[D]/[ED] = 5.20

D)[D]/[ED] = 5.20

E)[D']_T = 1.495* 10 ^-7 M

F)[D'] / [ED']  = 0.0579

Explanation:

E = 250 nM =2.5* 10 ^-7 mol/L , T=298.15 K

Dissociation constant of K_D = 1.3 μM (1.3 *10 ^-6 M)

E + D ⇄ ED → K_a = [ED] / [D][E]   (association constant)

ED ⇄ E + D → K_D = [E][D] / [ED]  (dissociation constant)

C)

[E] =2.5*10^-7 mol/L

K_D = 1.3* 10^-6 M

K_D = [E][D] / [ED] → [D]/[ED] = K_D / [E]

= [D]/[ED] = 1.3* 10 ^-6 / 2.5 *10^-7

= 13/25 * 10

=130/25 = 5.20

[D]/[ED] = 5.20

D)

ΔG =RTln Kd

ΔG_2 for E and D = 1.987 * 298.15 * ln 1.3*10^-6

ΔG_2 592.454 * [ln 1.3 +ln 10^-6]

ΔG_1 = 592.424 [0.2623 - 13.8155]

ΔG_2 = -592.424 * 13.553

ΔG_1 = -8184.633 cal/ mol

ΔG_1 = -8184.633  * 4.18 J/mol = -34244.508 J?mol

ΔG_1 = -34.245 KL/mol

so, ΔG_2 = ΔG_1 - 10.5 KJ/mol

ΔG_2 = -34.245 - 10.5

ΔG_2 = -44.745KJ / mol

ΔG_2 =RT ln K_D

-44.745 *10^3

=8.314 *298.15 lnK_D

lnK_D' = - 44745 / 2478.81 g

ln K_D' = -18.051

K_D' = -18.051

K_D' = e^-18.051

[D]/[ED] = 5.20

E)

[E] = 2.5* 10 ^-7 mol/ L = a

K_D' = [E][D] / [ED']                                  E +D' → ED'

K_D' = a/2(x-(a/2) / (a/2)

KD' = x - a/2

=2.447 *10^-8 = (2.5/2) * 10^-7

x=2.447 * 10^-8 + 1.25 * 10^-7

x = 2.447 *10^-8 + 1.25 * 10 ^-7

x= 10^-7 [1.25 + 0.2447]

x = 1.4947 * 10^-7

[D']_T = 1.495* 10 ^-7 M

F)

K_D' = [E][D'] / [ED']

[D'] / [ED'] = KD' / [E]

[D'] / [ED'] = 1.447 *10^-8 / 2.5* 10^-7

[D'] / [ED'] = 0.5788 * 10^-1

[D'] / [ED']  = 0.0579

5 0
3 years ago
Why are chemists interested in studying thermochemistry? a. Heat is often absorbed during reactions.b. Heat is often released du
Wittaler [7]

Answer:

a. Heat is often absorbed during reactions.

c. Heat is often released during chemical reactions.

Explanation:

Thermochemistry -

The study of thermochemistry involve the change in the amount of heat , during any physical or chemical process , is referred to as thermodynamics .

The focus of thermochemistry is on the changing amount of energy in the form of heat , on the system with respect to the surroundings .

The process like boiling , melting , sublimation , may require energy or releases energy , and hence are studied under thermochemistry .

Hence , from the given question ,

The correct options are -  a , c.

6 0
3 years ago
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