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kap26 [50]
3 years ago
11

In poor quality fireworks what will you notice and why

Chemistry
2 answers:
anastassius [24]3 years ago
8 0
The best answer I could find was when you Google it, that the fuse is of poor quality. I cannot leave you a link, but you can find it for yourself. Put in poor quality fireworks and all sorts of things will pop up. No pun intended.
Kisachek [45]3 years ago
7 0

Answer:

Explanation:

Hello!

Low quality fireworks have loosely bound mortars, shells and cannon fuses. Moreover, there are mighty chances that the cannon fuse or the visco fuse of the firework would be inappropriately small and have loosely wrapped protective layers. A good quality firework would always have a long cannon fuse with minimum of three protective layers wrapped around it, tightly. The three layers are, invariably, a combination of usual and lacquer coated wires. While the usual wires provide mechanical strength, the lacquer coated ones provide water resistance to the fuse and keep the fuse from falling apart.

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Tritium 3 1H decays to 3 2He by beta emission. Find the energy released in the process. Answer in units of keV.
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Answer:

The energy released in the decay process = 18.63 keV

Explanation:

To solve this question, we have to calculate the binding energy of each isotope and then take the difference.

The mass of Tritium = 3.016049 amu.

So,the binding energy of Tritium =  3.016049 *931.494 MeV

= 2809.43155 MeV.

The mass of Helium 3 = 3.016029 amu.

So, the binding energy of Helium 3 = 3.016029 * 931.494 MeV

= 2809.41292 MeV.

The difference between the binding energy of Tritium and the binding energy of Helium is: 32809.43155 - 2809.412 = 0.01863 MeV

1 MeV = 1000keV.

Thus, 0.01863 MeV = 0.01863*1000keV = 18.63 keV.

So, the energy released in the decay process = 18.63 keV.

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