All categories

4 years ago

In poor quality fireworks what will you notice and why

2 answers:

8 0

The best answer I could find was when you Google it, that the fuse is of poor quality. I cannot leave you a link, but you can find it for yourself. Put in poor quality fireworks and all sorts of things will pop up. No pun intended.

Kisachek [45]4 years ago

7 0

Answer:

Explanation:

Hello!

Low quality fireworks have loosely bound mortars, shells and cannon fuses. Moreover, there are mighty chances that the cannon fuse or the visco fuse of the firework would be inappropriately small and have loosely wrapped protective layers. A good quality firework would always have a long cannon fuse with minimum of three protective layers wrapped around it, tightly. The three layers are, invariably, a combination of usual and lacquer coated wires. While the usual wires provide mechanical strength, the lacquer coated ones provide water resistance to the fuse and keep the fuse from falling apart.

You might be interested in

Why are ions created in an ionic bond?

Dmitry [639]

Ionic bounds are formed due to the electrostatic attraction between oppositely charged ions in a chemical compound.
The atom that loses the electrons becomes a positively charged ion (cation), while the one that gains them becomes a negatively charged ion (anion).

6 0

4 years ago

Calculate by (a)% weight and (b) %mole each of the elements present in sugar

Musya8 [376]

Explanation:

Molecular mass of sugar = $C_{12}H_{22}O_{11}$ : = 432 g/mol

Atomic mass of carbon atom = 12 g/mol

Atomic mass of hydrogen atom = 1 g/mol

Atomic mass of oxygen atom = 16 g/mol

a) Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of compound}}\times 100$

Percentage of carbon by weight in $C_{12}H_{22}O_{11}$ :

$\frac{12\times 12 g/mol}{342 g/mol}\times 100=42.10\%$

Percentage of hydrogen by weight in $C_{12}H_{22}O_{11}$ :

$\frac{22\times 1g/mol}{342 g/mol}\times 100=6.43\%$

Percentage of oxygen by weight in $C_{12}H_{22}O_{11}$ :

$\frac{11\times 16g/mol}{342 g/mol}\times 100=51.46\%$

b) Percentage of mole each of the elements present in sugar:

= $\frac{\text{Moles of atoms of an element}}{\text{total moles of all types of atoms}}\times 100$

In mole of sugar we have 12 moles of carbon atom , 22 moles of hydrogen atoms and 11 moles of oxygen atoms.

Percentage of carbon by mole in $C_{12}H_{22}O_{11}$ :

$\frac{12 mol}{45 mol}\times 100=26.66\%$

Percentage of hydrogen by mole in $C_{12}H_{22}O_{11}$ :

$\frac{22 mol}{45 mol}\times 100=48.88\%$

Percentage of oxygen by mole in $C_{12}H_{22}O_{11}$ :

$\frac{11 mol}{45 mol}\times 100=24.44\%$

7 0

4 years ago

Find the force it would take to accelerate an 800-kg car at a rate of 5m/s2.

laila [671]

Force= mass•acceleration

Force=800•5

Force=4000 N

3 0

3 years ago

Read 2 more answers

Vhich of the following equations is correctly balanced?

Eva8 [605]

Answer:

option 3.

2Cr(NO₃)₃ + 3 FeSO₄ → 3 Fe(NO₃)₂ + Cr₂(SO₄)₃

Explanation:

Balance Chemical Equation:

A balanced chemical equation is that in which the number of the reactant atoms equal to the number of the product atom.

For example if the oxygen at the reactant side is 4, the number of oxygen must be 4 on the product side.

Solution

Check each equation one by one

1. Cr(NO₃)₃ + 2 FeSO₄ → 2 Fe(NO₃)₂ + Cr₂(SO₄)₃

Number of atoms of Reactant:

Cr = 1

N = 3

O = 17

Fe = 2

S = 2

Number of atoms of Reactant:

Cr = 2

N = 4

O = 24

Fe = 2

S = 3

So this is not a balance equation as the atoms of the reactant atom not equal to the product atoms.

___________________________________

2. 2Cr(NO₃)₃ + 2 FeSO₄ → 2 Fe(NO₃)₂ + Cr₂(SO₄)₃

Number of atoms of Reactant:

Cr = 2

N = 6

O = 26

Fe = 2

S = 2

Number of atoms of Reactant:

Cr = 2

N = 4

O = 24

Fe = 2

S = 3

So this is not a balance equation as the atoms of the reactant atom not equal to the product atoms.

___________________________________

2Cr(NO₃)₃ + 3 FeSO₄ → 3 Fe(NO₃)₂ + Cr₂(SO₄)₃

Number of atoms of Reactant:

Cr = 2

N = 6

O = 30

Fe = 3

S = 3

Number of atoms of Reactant:

Cr = 2

N = 6

O = 30

Fe = 3

S = 3

So this is a balance equation as the atoms of the reactant atom are equal to the product atoms.

Note** you write Cu and Cl instead of Cr, So that was also corrected.

5 0

4 years ago

Why are the coefficients before a chemical symbol important?F. They show the number of elements in each molecule.G. They i

Valentin [98]

Answer:They indicate the number of molecules of each substance

Explanation:

When we write chemical reaction equations, we usually put a number before the symbol of each reactant.

These coefficient shows the number of molecules of that specie that is involved in the balanced reaction equation for the reaction.

These coefficients are important because they are used in carrying out stoichiometric calculations.

7 0

3 years ago