All categories

3 years ago

In poor quality fireworks what will you notice and why

2 answers:

8 0

The best answer I could find was when you Google it, that the fuse is of poor quality. I cannot leave you a link, but you can find it for yourself. Put in poor quality fireworks and all sorts of things will pop up. No pun intended.

Kisachek [45]3 years ago

7 0

Answer:

Explanation:

Hello!

Low quality fireworks have loosely bound mortars, shells and cannon fuses. Moreover, there are mighty chances that the cannon fuse or the visco fuse of the firework would be inappropriately small and have loosely wrapped protective layers. A good quality firework would always have a long cannon fuse with minimum of three protective layers wrapped around it, tightly. The three layers are, invariably, a combination of usual and lacquer coated wires. While the usual wires provide mechanical strength, the lacquer coated ones provide water resistance to the fuse and keep the fuse from falling apart.

You might be interested in

Los isomeros ópticos

krek1111 [17]

Answer:

Los isómeros ópticos son dos compuestos que contienen el mismo número y tipo de átomos, y enlaces (es decir, la conectividad entre los átomos es la misma), y diferentes disposiciones espaciales de los átomos, pero que tienen imágenes especulares no superponibles. Cada estructura de imagen especular no superponible se denomina enantiómero.

Explanation

7 0

3 years ago

- How many grams of nitrogen (N2) are needed to react with 435.2 g of oxygen (02) in the following equation?

Llana [10]

Explanation:

I think the answer is this for a better check mass- mass ratio in stoichiometry lesson

5 0

2 years ago

Substances that are considered acidic are also called alkaline, true or false

V125BC [204]

False
Alkaline is something we use everyday
Acid is something sour eg lemons

7 0

3 years ago

Read 2 more answers

The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process. In the first step, manganese(I

ale4655 [162]

Answer:

The answer is "6.52 kg and 13.1 kg"

Explanation:

For point a:

$Actual\ yield = 6.52 \ kg\\\\Percent \ yield= 66\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical\ yield} \times 100 \%\\\\Theoretical\ yield \ of \ MnO_2 = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\=\frac{6.52 \ kg}{66 \%} \times 100\% =9.88 \ kg\\\\$

Equation:

$3MnCO_3 +O_2 \longrightarrow 2MnO_2 + 2CO_2\\\\$

Calculating the amount of $MnCO_3$

$= 9.88 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ MnO_2}{86.94 \ g} \times \frac{2 \ Mol \ MnCO_3}{2 \ mol \ MnO_2} \times \frac{114.95\ g}{1 \ mol \ MnCO_3 }\times \frac{1\ kg}{1000\ g}\\\\= 13.1 \ kg$

For point b:

$Actual\ yield = 4.0 \ kg\\\\Percent\ yield=97.0\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical \ yield} \times 100 \% \\\\Theoretical \ yield\ of\ Mn = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\$

$=\frac{4.0 \ kg}{97.0\%} \times 100\% =4.12 \ kg$

Equation:

$3MnO_2 +4AL \longrightarrow 3Mn + 2AL_2O_3\\\\$

Calculating the amount of $MnO_2:$

$= 4.12 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ Mn}{54.94 \ g} \times \frac{3 \ Mol \ MnO_2}{3 \ mol \ Mn} \times \frac{86.94 \ g}{1 \ mol \ MnO_2 }\\\\= 6516 \ g \\\\=6.52 \ kg\\\\$

7 0

3 years ago

Hello can you please help me to solve above fill in the blank questions

LiRa [457]

Answer:

C2H5OH is a formula of ethyl alchol or ethanol.

alkenes are characterisized by carbon-carbon double bond.

burning is an example of exothermic reaction

atomic number of element is x the symbol of its ion is +1 bcz it will lose one electron

if temperature increases then rate of chemical reaction increases

Explanation:

i hope this will help you :)

7 0

3 years ago