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sdas [7]
2 years ago
13

SCIENCE why is it important to distinguish the two types of crust?

Chemistry
2 answers:
kiruha [24]2 years ago
8 0

Answer:

It is important to identify it because the two types of crust are made up of two different types of rock

Explanation:

Have a nice day

Yuri [45]2 years ago
4 0

Answer:

It is important to identify it because the two types of crust are made up of two different types of rock

Explanation:

Hope i helped you

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Draw the product formed when 2-butanol undergoes reaction with TsCl and Et3N. CH3C6H4SO2Cl.
Pie

Answer:

Explanation:

In organic chemistry, the reaction between 2-butanol with TsCl and Et3N is known as the tosylation of the alcohol hydroxyl group. Alcohol is being changed to tosylate by the use of tosyl chloride under the influence of a base. Tosylation of alcohol is an example of a nucleophilic substitution reaction. From the image attached below, we will see how the reaction between 2-butanol proceed into the product by using tosyl chloride and a base(Et3N).

4 0
3 years ago
Please help I need these answers
Burka [1]

Answer:

2 a

element pure form cannot broken down

3 b

Chemical change chemical R×N

(R×N = reaction)

4c homogeneous solution

Yield = Yield (reaction yield): A measure of a chemical reaction's efficiency, as a ratio of moles of product to moles of reactant. Usually expressed as a percentage. % Yield = Moles of product.

Explanation:

5 0
2 years ago
There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
grandymaker [24]

\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

Assuming complete decomposition of both samples,

  • m(\text{Hg}) = m(\text{residure})
  • m(\text{O}) = m(\text{loss})

First compound:

  • m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g

n = m/M; 0.6498 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.048 \; g  / 16 \; g \cdot mol^{-1}= 0.003 \; mol
  • n(\text{Hg atoms}) = 0.6018 \; g  / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol

Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

Similarly, for the second compound

  • m(\text{O}) = m(\text{loss}) = 0.016 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012  \; g

n = m/M; 0.4172 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.016 \; g  / 16 \; g \cdot mol^{-1}= 0.001 \; mol
  • n(\text{Hg atoms}) = 0.4012 \; g  / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol

n(\text{Hg}) : n(\text{O}) \approx  2:1 and therefore the empirical formula

\text{Hg}_{2} \text{O}.

8 0
3 years ago
State four uses of protein in human body??​
Mamont248 [21]

Your body uses it to build and repair tissue. You need it to make enzymes, hormones, and other body chemicals. It is an important building block of bones, muscles, cartilage, skin, and blood. Along with fat and carbohydrates.

4 0
2 years ago
Read 2 more answers
PLEASE PLEASE PLEASE HELPPP
Ivan
I believe that the answer is B
8 0
3 years ago
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