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miskamm [114]
3 years ago
5

Fuel cell cars that use hydrogen as fuel have the potential to be quiet, produce low emissions, and require less maintenance tha

n gasoline cars. What negative effect might hydrogen fuel have on the environment?
Chemistry
2 answers:
storchak [24]3 years ago
5 0

Answer:

The production of hydrogen releases CO₂.

Explanation:

Hydrogen is not a primary fuel, it means that it is not available to be used directly, it must be produced. The production generally uses fossil fuels, and in that case, CO₂ is produced, which is a greenhouse gas (GHG).

So, to obtain that fuel, CO₂ is released, which has a negative effect on the environment because it intensifies the greenhouse effect and global warming.

Delvig [45]3 years ago
4 0
Advocates for the use of hydrogen fuel cells posit that unlike other sources of power, these fuel cells do not emit harmful carbon emissions in the air that cause pollution and affect global warming. Although the chemical process involves burning hydrogen<span>, it emits water, heat and other emissions but not carbon.

I hope my answer has come to your help. God bless and have a nice day ahead!
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Board cases involving eligibility or disciplinary issues that are resolved through a board agreed order
Wewaii [24]

Board instances involving eligibility or disciplinary issues that are addressed by a board-approved order public records and accessible on the BON's web page.

<h3>BON's web page</h3>

Board Position Statements are a way to give nurses guidance on topics that are important to the Board and relate to the safety of the public, but they do not have the legal force of law. In the context of the position statement's overall intent, each position statement is intended to offer direction. Board position statements are examined every year to determine their applicability and accuracy in light of current practice, the Nursing Practice Act, and Board regulations. In January 2022, the Board conducted its most recent evaluation.

It is possible to find a concise summary of the substance of the Position Statements, although it does not include all the specifics that are included in each Position Statement.

Learn more about BON's web page here:

brainly.com/question/16982080

#SPJ1

7 0
2 years ago
Instructions:
never [62]

Answer:

See explanation

Explanation:

A. Constitutional or structural isomers have the same molecular formula but different structural formulas.

B. Conformational isomers are compounds having the same atom to atom connectivity but differ by rotation about one or more single bonds.

C. Stereo isomers are compounds having the same molecular mass and atom to atom connectivity but different arrangement of atoms and groups in space.

I. Enantiomers are stereo isomers (optical isomers particularly) that are non-superimposable mirror images of each other.

II. Diasteromers are optical isomers that are not mirror images of each other.

Both diasteromers and enantiomers are types of optical isomers which in turn is one of the types of stereo isomers.

Stereo isomers differ from conformational isomers in that the arrangement of atoms in stereo isomers is permanent while conformational isomers results from free rotations in molecules about single bonds.

7 0
3 years ago
Select the correct answer. Which statement is true of a chemical change? A. It involves changes in the molecular structure. B. I
wolverine [178]
I think the answer is something within..
4 0
2 years ago
Read 2 more answers
Please help mee 11-14
Artemon [7]

Answer:

11. A)outward

12. B) inward

13. B) opaque

14. I really don't know (sorry)

Explanation:

7 0
3 years ago
The air inside a hot-air balloon is heated to 59.00 °C (Tinitial) and then cools to 39.00 °C (Tfinal). By what percentage does t
Mama L [17]

Answer:

6.1%

Explanation:

Assuming pressure inside balloon remains constant during the temperature change.

Therefore, as per Charles' law  at constant pressure,

\frac{V_1}{T_1} =\frac{V_2}{T_2}

T_2=39\°\ C=39+273=312\ K

T_1=59°\ C=273+59=332\ K

V_2=V_1\times \frac{T_2}{T_1} \\=V_1\times\frac{312}{332}\\=0.939V_1

Percentage change in volume

\%\ change\ in\ volume=\frac{V_1-0.939V_1}{V_1} \times 100\\=6.1\%

Change in volume of the balloon is 6.1%

4 0
3 years ago
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