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Zina [86]
3 years ago
12

Sarah's class is studying soils. Her teacher, Ms. Jones, stated that plants will growth in any soil type. Students in Sarah's cl

ass performed an experiment to see if Ms. Jones' statement is true. When they started the experiment, the students used the same type of plants, and all of the plants were the same size. Sunlight, amount of water, and air temperature were the same for all pots; only the soil type was changed. The results are seen in the table. Ms. Jones was partially correct: all the plants DID grow but not at the same rate. What conclusion can be drawn from the three test pots of soil?
A)The bigger the soil particle size, the better the plant growth.

B)Plants grow best in soils that are a mixture of sand, clay, and loam.

C)The smaller the soil particles, the more water and air available for plant growth.

D)Sandy holds water for short periods of time; low water means less plant growth.
Chemistry
2 answers:
AnnZ [28]3 years ago
7 0
The answer in c. I think this because it’s the most logical answer, and based on my experience with plants, the smaller the soil particles, the more air and water is available! I hope this helps:)
ivanzaharov [21]3 years ago
4 0

Answer: C)The smaller the soil particles, the more water and air available for plant growth.

Explanation:

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CO(g)+2H2(g)⇌CH3OH(g)CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial concentrations o
Katarina [22]

Answer:

9.4

Explanation:

The equation for the reaction can be represented as:

CO_{(g)}    +      2H_2O_{(g)}   ⇄  CH_3OH_{(g)}

The ICE table can be represented as:

                                  CO_{(g)}    +      2H_2_{(g)}   ⇄  CH_3OH_{(g)}

Initial                          0.27             0.49              0.0

Change                      -x                  -2x                 x

Equilibrium               0.27 - x         0.49 -2x          x

We can now say that the concentration of  CH_3OH_{(g)} at equilibrium is x;

Let's not forget that at equilibrium  CH_3OH_{(g)} = 0.11 M

So:

x =  [CH_3OH_{(g)}] = 0.11 M

[CO_{(g)}] = 0.27 - x

[CO_{(g)}] = 0.27 - 0.11

[CO_{(g)}] = 0.16 M

[2H_2_{(g)}] = (0.49 - 2x)

[2H_2_{(g)}] = (0.49 - 2(0.11))

[2H_2_{(g)}] = 0.49 - 0.22

[2H_2_{(g)}] = 0.27 M

K_C = \frac{[CH_3OH]}{[CO][H_2]^2}

K_C = \frac{(0.11)}{(0.16)[(0.27)^2}

K_C = 9.4307

K_C = 9.4

∴ The equilibrium constant at that temperature = 9.4

8 0
2 years ago
Order the following from smallest to largest
Dmitry [639]

1. Quark

2. Electron

3. Proton and Neutron

4. Nucleus

5. Atom

6. Molecule

8 0
3 years ago
The strength of an acid or a base is determined by the
Tresset [83]
Ionization/dissociation, Ka, larger, concentration/molarity, mostly/completely, strong, weak, base, water, acid, strong
3 0
3 years ago
Question 25 a chemist determined by measurements that 0.020 moles of mercury participated in a chemical reaction. calculate the
sammy [17]
To solve this question, we first need to know the mass of one mole of mercury. This can be done by checking the periodic table.

From the periodic table, we can see that:
molar mass of mercury = 200.59 grams/mole.

From the measurements, the chemist found that the participated amount of mercury is 0.02 moles.

We can simply determine the mass of 0.02 moles by doing cross multiplication as follows:
mass of 0.02 moles = (0.02 x 200.59) / 1 = 4.0118 grams

Rounding the answer to 2 significant digits, we get:
mass of 0.02 moles = 4.01 grams
4 0
3 years ago
PLZ ANSWER
satela [25.4K]

Answer:

B. The student should model a convex lens because it directs light toward the center of the lens.

Explanation:

Lenses are optical devices that work on the principle of refraction.

Refraction is a phenomenon of wave (such as light waves) that occurs when a ray of light crosses the interface between two mediums with different optical density: when this occurs, the ray of light bends and change speed.

In particular, there are two types of lenses:

  • Convex lenses: these lenses are curved outward at their center, therefore the rays of light coming from infinite distance (parallel to the axis) are all focused into a point of the lens, called principal focus. Therefore, a convex lens directs lights towards this point.
  • Concave lenses: these lenses are curved inward at their center, therefore the rays of light coming from infinite distance are bent away from the principal focus. Therefore, this is a diverging lens, as the rays of light do not converge.

So, the correct answer is

B. The student should model a convex lens because it directs light toward the center of the lens.

7 0
3 years ago
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