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kramer
3 years ago
6

Distilled vinegar contains a solution of acetic acid (CH3CO2H) in H2O. What is the concentration of the solution that results fr

om diluting 500 ml of 0.839 M vinegar solution to 2.5 L?
Chemistry
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

0.168M

Explanation:

We obtained the following information from the question:

C1 = 0.839 M

V1 = 500mL = 500/1000 = 0.5L

C2 =?

V2 = 2.5L

Using the dilution formula, we can obtain the concentration of the diluted solution as follows:

C1V1 = C2V2

0.839 x 0.5 = C2 x 2.5

Divide both side by 2.5

C2 = (0.839 x 0.5) /2.5

C2 = 0.168M the concentration of the diluted solution is 0.168M

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How many moles in 4.93 x 10E23 atoms of silver?
leva [86]
<h3>Answer:</h3>

0.819 mol Ag

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

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<u>Stoichiometry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

4.93 × 10²³ atoms Ag

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 4.93 \cdot 10^{23} \ atoms \ Ag(\frac{1 \ mol \ Ag}{6.022 \cdot 10^{23} \ atoms \ Ag})
  2. Divide:                              \displaystyle 0.818665 \ mol \ Ag

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.818665 mol Ag ≈ 0.819 mol Ag

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2 years ago
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