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kramer
3 years ago
6

Distilled vinegar contains a solution of acetic acid (CH3CO2H) in H2O. What is the concentration of the solution that results fr

om diluting 500 ml of 0.839 M vinegar solution to 2.5 L?
Chemistry
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

0.168M

Explanation:

We obtained the following information from the question:

C1 = 0.839 M

V1 = 500mL = 500/1000 = 0.5L

C2 =?

V2 = 2.5L

Using the dilution formula, we can obtain the concentration of the diluted solution as follows:

C1V1 = C2V2

0.839 x 0.5 = C2 x 2.5

Divide both side by 2.5

C2 = (0.839 x 0.5) /2.5

C2 = 0.168M the concentration of the diluted solution is 0.168M

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Answer:

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Explanation:

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:

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113.8g

Explanation:

Statement of problem: mass of 1.946mole of NaCl

Given parameters:

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Unknown: mass of NaCl

Solution

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