Question

containing two H and one Se atoms. How many single bonds, double bonds, triple bonds, and unshared pairs of electrons are on the central atom, in that order?

Answer 1

Draw the Lewis structure for the molecule containing two H and one Se atoms. How many single bonds ,double bonds, triple bonds, and unshared pairs of electrons are on the central atom, in that order?

1)3, 0, 0, 1 2)1, 0, 1, 0 3)0, 1, 1, 0 4)0, 2, 0, 0 5)2, 0, 0, 2 6)1, 1, 0, 1 7)4, 0, 0, 0 8)None of these 9)0, 0, 1, 110)2, 1, 0, 0

Answer:

5)2, 0, 0, 2

Explanation:

The answers are to be written in this order; single bonds ,double bonds, triple bonds, and unshared pairs of electrons.

H2Se is called Hydrogen selenide, hydroselenic acid, selenium hydride, or selane, it is an inorganic compound. It contains hydrogen and selenide ions.

It has a bent shape with 6 valence electrons.

H2Se  exhibit dipole-dipole intermolecular forces. H2Se have two lone pairs, the compound complete its octet by mutually sharing their electrons as shown in the figure below.

After sharing their electrons Se now has 8 electrons and the two H have 2 electrons each. But Se also has two lone pairs of electron.

Thus the lewis structure will be as drawn in the attached image.

There are 2 single bond, 0 double bond, 0 triple bond, and 2 unshared pairs of electrons thus the correct answer from the options is 2, 0, 0, 2.

Answer 2

Draw the Lewis structure for the molecule containing two H and one Se atoms.How many single bonds ,double bonds, triple bonds, and unshared pairs of electrons are on the central atom, in that order?

1)3, 0, 0, 1

2)1, 0, 1, 0

3)0, 1, 1, 0

4)0, 2, 0, 0

5)2, 0, 0, 2

6)1, 1, 0, 1

7)4, 0, 0, 0

8)None of these

9)0, 0, 1, 1

10)2, 1, 0, 0

Answer:

The correct answer is (5) 2, 0, 0, 2

(Lewis structure in attached image)

Explanation:

In $H_{2}Se$ , the central atom Se is attached to two H atoms. Se has 6 valence electrons while hydrogen has one valence electron and since there are two hydrogen atoms,there will be 2 valence electrons for two hydrogen atoms. Therefore there are 8 valence electrons in total

Se= 1 × 6 $e^{-}$

 H= 2 × 1 $e^{-}$

total valence electrons= 8 $e^{-}$

Thus the lewis structure will be as drawn in the attached image.

There are 2 single bond, no double bond, no triple bond, and 2 unshared pairs of electrons hence the correct answer from the options is 2, 0, 0, 2