Answer:
101.2%
Explanation:
Given:
Theoretical yield of the precipitate = 0.914 g
Actual yield of the precipitate = 0.925 g
Now, the percent yield is given as a ratio of actual yield by theoretical yield expressed as a percentage.
Framing in equation form, we have:

Now, plug in 0.925 g for actual yield, 0.914 g for theoretical yield and solve for % yield. This gives,

Therefore, the percent yield is 101.2%.
Rate constant = .17 maybe I don't really know tho so don't take my word for it. #woot woot
Answer:
The correct answer is A. Barium Chloride
Explanation:
You can find the answer on google for this
Answer:
V = 10.3 L
Explanation:
Given data:
Mass of methane = 6.40 g
Volume of CO₂ produced = ?
Temperature = 35°C (35+273 = 308 K)
Pressure = 100.0 KPa (100.0/101 = 0.98 atm)
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of CH₄:
Number of moles = mass/molar mass
Number of moles = 6.40 g/ 16 g/mol
Number of moles = 0.4 mol
Now we will compare the moles of CO₂ with CH₄.
CH₄ : CO₂
1 : 1
0.4 : 0.4
Volume of CO₂:
Formula:
PV = nRT
0.98 atm ×V = 0.4 mol ×0.0821 atm.L/mol.K × 308 K
0.98 atm ×V = 10.11 atm.L
V = 10.11 atm.L /0.98 atm
V = 10.3 L