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Firdavs [7]
3 years ago
9

Molarity and Dilution

Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
6 0

Answer: The moles needed are 0.01.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute (CuSO_4.5H_2O) = ?  

V_s = volume of solution in ml  

Now put all the given values in the formula of molarity, we get

0.10=\frac{n\times 1000}{100}

n=\frac{0.10\times 100}{1000}=0.01

Therefore, the moles needed are 0.01.

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Starting with 0.657 g of lead(II) nitrate, a student collects 0.925 g of precipitate. If the calculated mass of precipitate is 0
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Answer:

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Explanation:

Given:

Theoretical yield of the precipitate = 0.914 g

Actual yield of the precipitate = 0.925 g

Now, the percent yield is given as a ratio of actual yield by theoretical yield expressed as a percentage.

Framing in equation form, we have:

\%\ yield=\frac{Actual\ yield}{Theoretical\ yield}\times 100

Now, plug in 0.925 g for actual yield, 0.914 g for theoretical yield and solve for % yield. This gives,

\%\ yield=\frac{0.925\ g}{0.914\ g}\times 100\\\\\%\ yield=1.012\times 100\\\\\%\ yield=101.2\%

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What volume of carbon dioxide is produced when 6.40 g of methane gas, CH4 (g), reacts with excess oxygen? All gases are at 35.0C
Mandarinka [93]

Answer:

V = 10.3 L

Explanation:

Given data:

Mass of methane = 6.40 g

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Temperature = 35°C (35+273 = 308 K)

Pressure = 100.0 KPa (100.0/101 = 0.98 atm)

Solution:

Chemical equation:

CH₄ +  2O₂        →       CO₂ + 2H₂O

Number of moles of CH₄:

Number of moles = mass/molar mass

Number of moles = 6.40 g/ 16 g/mol

Number of moles = 0.4 mol

Now we will compare the moles of CO₂ with CH₄.

         CH₄          :         CO₂

           1             :           1

        0.4            :         0.4

Volume of CO₂:

Formula:

PV = nRT

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V = 10.11 atm.L /0.98 atm

V = 10.3 L

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