Given:
The length of diagonals of a rhombus are 12 ft and 5 ft.
To find:
The area of the rhombus
Solution:
Area of a rhombus is:
Where, are two diagonals of the rhombus.
It is given that the length of diagonals of the rhombus are 12 ft and 5 ft.
Putting , we get
Therefore, the area of the rhombus is 30 square ft.
Pretty sure it’s the bottom right option
Answer:
1) x=-3 (D)
2) x=10 (G)
3) x=1 (A)
4) x=3 (C)
Step-by-step explanation:
F.301 ft2 (the tiny two at the top not a regular 2)
G.322 ft2 (the tiny two at the top not a regular 2)
H.331 ft2 (the tiny two at the top not a regular 2)
I.352 ft2 (the tiny two at the top not a regular 2)
Answer: length of the rectangular firls = 50
and the breadth = x-20m= 50-20m =30m
Step-by-step explanation:
The perimeter of a rectangle is given as 2(l+b)
let the length be represented as x
such that the breadth = x-20m
so our expression for the perimeter of the rectangular firls becomes
Perimeter = 2l+ 2b
160= 2x + 2 ( x-20)
160= 2x+ 2x-40
160+40 =4x
200= 4x
x= 200/4
x= 50
So the length of the rectangular firls = 50
and the breadth = x-20m= 50-20m =30m