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DochEvi [55]
3 years ago
7

Suppose that the number of times that Vampire Bill gets attacked by Hep V in a given year is a Poisson random variable with para

meter λ = 5. Now, he discovered a new drug (based on large quantities of vitamin C) that has just been marketed to protect from Hep V. It claims to reduce the Poisson parameter to λ = 3 for 75% of the population. For the rest of the population, the drug has no appreciable effect on Hep V. If Bill tries the drug for a year and only had 2 Hep V attacks in that time, how likely is it that the drug was beneficial for him?
Engineering
1 answer:
Masteriza [31]3 years ago
6 0

Answer:

Explained

Explanation:

let probability of getting attached by Hep(V) without benefit of new drug =P(A)

probability of getting attached by Hep(V) with new drug =P(B)

hence probability that Hep V attack are 2 given he is without benefit of drug =P(C|A) =\small e^{-\lambda }\lambda ^{x}/x! where \small \lambda=5 ,x=2

=0.084

and probability that Hep V attack are 2 given he is with new drug =P(C|B) =\small e^{-\lambda }\lambda ^{x}/x! where \small \lambda=3 ,x=2

=0.224

hence probability of Hep V attack are 2 =P(C) =P(A)*P(C|A) +P(B)*P(C|B) =0.25*0.084+0.224*0.75=0.189

from above probability that drug is beneficial given he had 2 Hep V attacks =P(B)*P(C|B)/P(C) =0.224*0.75/0.189 =0.8889

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Steam enters a turbine at 8000 kPa, 440oC. At the exit, the pressure and quality are 150 kPa and 0.19, respectively.
levacccp [35]

Answer:

\dot W_{out} = 3863.98\,kW

Explanation:

The turbine at steady-state is modelled after the First Law of Thermodynamics:

-\dot Q_{out} -\dot W_{out} + \dot m \cdot (h_{in}-h_{out}) = 0

The specific enthalpies at inlet and outlet are, respectively:

Inlet (Superheated Steam)

h_{in} = 3353.1\,\frac{kJ}{kg}

Outlet (Liquid-Vapor Mixture)

h_{out} = 890.1\,\frac{kJ}{kg}

The power produced by the turbine is:

\dot W_{out}=-\dot Q_{out} + \dot m \cdot (h_{in}-h_{out})

\dot W_{out} = -2.93\,kW + (1.57\,\frac{kg}{s} )\cdot (3353.1\,\frac{kJ}{kg} - 890.1\,\frac{kJ}{kg} )

\dot W_{out} = 3863.98\,kW

8 0
3 years ago
Compute the repeat unit molecular weight of PTFE. Also compute the number-average molecular weight for a PTFE for which the degr
MatroZZZ [7]

Answer:

a) the repeat unit molecular weight of PTFE MW = 100.015 g/mole

b) the number-average molecular weight for a PTFE for which the degree of polymerization is 10,000 щₙ = 1000150 g/mole

Explanation:

Given that;

PTFE which is also called Polytetrafluoroethylene

structure  of repeat unit of Polytetrafluoroethylene

(C2F4)n

a)

To compute the repeat unit molecular weight

we say

MW = 2( atomic weight of C ) + 4( atomic weight of F)

MW = 2 (12.0107) + 4 ( 18.9984)

MW = 100.015 g/mole

therefore the repeat unit molecular weight of PTFE MW = 100.015 g/mole

b)

To compute the number-average molecular weight for  PTFE of which the degree of polymerization is 10,000

we say

DP = щₙ / MW

where щₙ is the number of average molecular weight,

MW is the repeat unit molecular weight give as 100.015 g/mole

DP is degree of polymerization which is 10,000

Now we substitute

10,000 = щₙ / 100.015

щₙ = 10,000 × 100.015

щₙ = 1000150 g/mole

Therefore the number-average molecular weight for a PTFE for which the degree of polymerization is 10,000 щₙ = 1000150 g/mole

3 0
3 years ago
10 litres of an ideal gas at 27°C and 12atm pressure is isothermally and reversibly expanded to a final pressure of 3atm.Calcula
Sliva [168]

Known :

V1 = 10 L

T1 = 27°C

P1 = 12 atm

P2 = 3 atm

Solution :

Work done in the process

W = P1 • V1 ln (P1 / P2)

W = (12 atm) • (10 L) ln (12 / 3)

W = 166.35 L • atm

W = 168.55 kJ

7 0
2 years ago
The contents of a tank are to be mixed with a turbine impeller that has six flat blades. The diameter of the impeller is 3 m. If
lions [1.4K]

Answer:

P=3.31 hp (2.47 kW).

Explanation:

Solution

Curve A in Fig1. applies under the conditions of this problem.

S1 = Da / Dt ; S2 = E / Dt ; S3 = L / Da ; S4 = W / Da ; S5 = J / Dt and S6 = H / Dt

The above notations are with reference to the diagram below against the dimensions noted. The notations are valid for other examples following also.

32.2

Fig. 32.2 Dimension of turbine agitator

The Reynolds number is calculated. The quantities for substitution are, in consistent units,

D a =2⋅ft

n= 90/ 60 =1.5 r/s

μ = 12 x 6.72 x 10-4 = 8.06 x 10-3 lb/ft-s

ρ = 93.5 lb/ft3 g= 32.17 ft/s2

NRc = (( D a) 2 n ρ)/ μ = 2 2 ×1.5×93.5 8.06× 10 −3 =69,600

From curve A (Fig.1) , for NRc = 69,600 , N P = 5.8, and from Eq. P= N P × (n) 3 × ( D a )5 × ρ g c

The power P= 5.8×93.5× (1.5) 3 × (2) 5 / 32.17 =1821⋅ft−lb f/s requirement is 1821/550 = 3.31 hp (2.47 kW).

5 0
3 years ago
A train which is traveling at 70 mi/hr applies its brakes as it reaches point A and slows down with a constant deceleration. Its
Ugo [173]

Answer:

a) 0 mi/s^2

b) 52 mi/s

Explanation:

Assuming the crossing is 1/2 mile past point A and that point B is near point A (it isn't clear in the problem)

The train was running at 70 mi/h at point A and with constant deceleration reachesn the crossing 1/2 mile away with a speed of 52 mi/h

The equation for position under constant acceleration is:

X(t) = X0 + V0 * t + 1/2 * a * t^2

I set my reference system so that the train passes point A at t=0 and point A is X = 0, so X0 = 0.

Also the equation for speed under constant acceleration is:

V(t) = V0 + a * t

Replacing

52 = 70 + a * t

Rearranging

a * t = 52 - 70

a = -18/t

I can then calculate the time it will take it to reach the crossing

1/2 * a * t^2 + V0 * t  - X(t) = 0

Replacing

1/2 (-18/t) * t^ + 70 * t - 1/2 = 0

-9 * t + 70 * t = 1/2

61 * t = 1/2

t = (1/2)/61 = 0.0082 h = 29.5 s

And the acceleration is:

a = -18/0.0082 = -2195 mi/(h^2)

To beath the train the car must reach the crossing in 29.5 - 4.3 = 25.2 s

X(t) = X0 + V0 * t + 1/2 * a * t^2

52 mi/h = 0.0144 mi/s

1/2 = 0 + 0.0144 * 25.2 + 1/2 * a * 25.2^2

1/2 = 0.363 + 317.5 * a

317.5 * a = 0.5 - 0.363

a = 0.137/317.5 = 0.00043 mi/s^2 (its almost zero)

The car should remain at about constant speed.

It will be running at the same speed.

4 0
3 years ago
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