This problem can be solved directly using stoichiometry.
We can actually see that for every mol of P4O10, there are 4 moles of P.
Therefore the total moles of P is:
moles P = 88.5 moles P4O10 * (4 moles P / 1 mole P4O10)
<span>moles P = 354 moles P</span>
Answer:
Mass = 57.05 g
Explanation:
Given data:
Volume of SO₂ = 20.0 L
Temperature = standard = 273 K
Pressure = standard = 1 atm
Mass of SO₂ = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm × 20.0 L / 0.0821 atm.L/ mol.K× 273 k
n = 20.0 / 22.41/mol
n = 0.89 mol
Mass of SO₂:
Mass = number of moles × molar mass
Mass = 0.89 mol × 64.1 g/mol
Mass = 57.05 g
It’s the 3d one
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