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svet-max [94.6K]
3 years ago
11

Please help me :) PLEASE HELP ME

Mathematics
1 answer:
Olegator [25]3 years ago
6 0
Number 3 is 11 degrees
Number four is 51 degrees.
Number 5 is 21 degrees
Number 7 is altitude
You might be interested in
Would appreciate the help
raketka [301]

Answer:

x° = 37°

Step-by-step explanation:

* Lets revise some facts of a circle

- The secant is a line intersect the circle in two points

- If two secants intersect each other in a point outside the circle,

 then the measure of the angle between them is half the difference

 of the measures of their intercepted arcs

* Now lets solve the problem

- There is a circle

- Two secants of this circle intersect each other in a point outside

  the circle

∴ The measure of the angle between them = 1/2 the difference of the

  measures of their intercepted arcs

∵ The measure of the angle between them is x°

∵ The measures of their intercepted arcs are 26° and 100°

- Use the rule above to find x

∴ x° = 1/2 [ measure of the large arc - measure of small arc]

∵ The measure of the large arc is 100°

∵ The measure of the small arc is 26°

∴ x° = 1/2 [100 - 26] = 1/2 [74] = 37°

∴ x° = 37°

4 0
3 years ago
−8(y 9)=−40 what does y equal
rewona [7]

-8(y 9) = -40

-72y = -40

y = 40/72 = 5/9

3 0
3 years ago
Read 2 more answers
A square is removed from the right hand corner
denis-greek [22]

Answer:

C im pretty sure

Step-by-step explanation:

Because the square taken out has a 4x4 area which is 16 and the area of the whole square used to be 14x14 which is 196 and if u subtract 16 from that you get 180

5 0
3 years ago
Read 2 more answers
stock a changed by -5.70 during the the day stock b changed be 2 1/3 times that amount. how much did stock b change during the d
Romashka-Z-Leto [24]

Answer: -13.3

Step-by-step explanation:

2 1/3 * -5.70 = -13.3

7 0
4 years ago
Please explain how you came to your answer, need help ASAP. Will give brainliest
shusha [124]
The vertex is the high point of the curve, (2, 1). The vertex form of the equation for a parabola is
.. y = a*(x -h)^2 +k . . . . . . . for vertex = (h, k)

Using the vertex coordinates we read from the graph, the equation is
.. y = a*(x -2)^2 +1

We need to find the value of "a". We can do that by using any (x, y) value that we know (other than the vertex), for example (1, 0).
.. 0 = a*(1 -2)^2 +1
.. 0 = a*1 +1
.. -1 = a

Now we know the equation is
.. y = -(x -2)^2 +1

_____
If we like, we can expand it to
.. y = -(x^2 -4x +4) +1
.. y = -x^2 +4x -3

=========
An alternative approach would be to make use of the zeros. You can read the x-intercepts from the graph as x=1 and x=3. Then you can write the equation as
.. y = a*(x -1)*(x -3)
Once again, you need to find the value of "a" using some other point on the graph. The vertex (x, y) = (2, 1) is one such point. Subsituting those values, we get
.. 1 = a*(2 -1)*(2 -3) = a*1*-1 = -a
.. -1 = a
Then the equation of the graph can be written as
.. y = -(x -1)(x -3)
In expanded form, this is
.. y = -(x^2 -4x +3)
.. y = -x^2 +4x -3 . . . . . . same as above
5 0
4 years ago
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