Aqueous acetic acid is neutralized by aqueous barium hydroxide. express your answer as a balanced molecular equation. identify a

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Stella [2.4K]

3 years ago

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Aqueous acetic acid is neutralized by aqueous barium hydroxide. express your answer as a balanced molecular equation. identify a

ll of the phases in your answer.

Chemistry

2 answers:

Studentka2010 [4] · Answer 1 · 2022-04-06T14:14:58+03:00

The balanced molecular equation for the given reaction is:

$2CH_3COOH(aq) \ + \ Ba(OH)_2(aq) \rightarrow \ Ba(CH_3COO)_2(aq) + 2H_2O(l).$

<h3>FURTHER EXPLANATION</h3>

To check that the equation is balanced count how many atoms are present for each element in the reactant and product side. If they are the same before and after reaction for all elements, then the reaction is deemed balanced.

The atom counting for the equation is shown below:

$2CH_3COOH(aq) \ + \ Ba(OH)_2(aq) \rightarrow \ Ba(CH_3COO)_2(aq) + 2H_2O(l).$

<u>Reactants </u> → <u>Products</u>

C: (2 x 2) =4 C: (2 x 2) = 4

H: (2 x 4) + (1 x 2) =10 H: (3 x 2) + (2 X 2) = 10

O: (2 x 2) + (1 x 2) = 6 O: (2 x 2) + (2 x 1) = 6

Ba: 1 Ba: 1

Since the number of atoms of each element are similar in the reactants and products, the equation is balanced.

To determine the state of the substances, consider their solubility.

The reactants are both aqueous (aq) as indicated in the problem.

The first product, $Ba(CH_3COO)_2$ is aqueous (aq) because based on the solubility rule, it will dissolve in water. Acetates are generally soluble.

The other product is water which will be liquid (l) since it is the solvent used to dissolve the substances.

<h3>LEARN MORE</h3>

Solubility Rules brainly.com/question/12984314
Net Ionic Equation brainly.com/question/12980075

Keywords: acid-base, neutralization, balancing equations, molecular equation

Aliun [14] · Answer 2 · 2022-04-06T15:56:42+03:00

The balanced molecular equation for reaction of acetic acid and barium hydroxide is as follows:

$\boxed{2\text{CH}_3\text{COOH}(aq)+\text{Ba(OH)}_2(aq)\rightarrow\left(\text{CH}_3\text{COO}\right)_2\text{Ba} (aq)+2\text{H}_2\text{O}(l)}$

Further Explanation:

Neutralization reaction:

This reaction occurs when acid and base react with each other and salt and water are formed. Since these reactions neutralize excess amount of hydrogen or hydroxide ions in the solution, it is named so.

Acetic acid is weak acid and barium hydroxide is strong base. Both react with each other to form salt and water and neutralization reaction takes place.

Chemical equations are written in following different types of equations:

Molecular equations
Total ionic equations
Net ionic equations

In molecular equations, reactants and products are present in undissociated form. Total ionic equations involve all different types of ions involved in the reactions. But in net ionic equations, only useful ions are written.

In this reaction, $\text{CH}_3\text{COOH}$ , reacts with $\text{Ba(OH)}_2$ to form $\left(\text{CH}_3\text{COO}\right)_2\text{Ba}$ and $\text{H}_2\text{O}$ . Here, $\text{CH}_3\text{COOH}$ , $\text{Ba(OH)}_2$ and $\left(\text{CH}_3\text{COO}\right)_2\text{Ba}$ are present in aqueous phase while $\text{H}_2\text{O}$ is present in liquid phase. Unbalanced molecular equation becomes,

$\text{CH}_3\text{COOH}(aq)+\text{Ba(OH)}_2(aq)\rightarrow\left(\text{CH}_3\text{COO}\right)_2\text{Ba} (aq)+\text{H}_2\text{O}(l)$

Number of atoms of all elements on both sides of reaction is written.

On reactant side,

Number of C atom is 1.

Number of H atoms is 6.

Number of Ba atoms is 1.

Number of O atoms is 4.

On the product side,

Number of C atom is 2.

Number of H atoms is 8.

Number of Ba atoms is 1.

Number of O atoms is 5.

Initially, atoms other than carbon, oxygen, and hydrogen are balanced by multiplying with some number on any side. Ba atoms are balanced on both sides. So carbon, hydrogen and oxygen atoms are balanced now. For this, $\text{CH}_3\text{COOH}$ is multiplied by 2 and $\text{H}_2\text{O}$ by 2. Now the balanced equation is as follows:

$2\text{CH}_3\text{COOH}(aq)+\text{Ba(OH)}_2(aq)\rightarrow\left(\text{CH}_3\text{COO}\right)_2\text{Ba} (aq)+2\text{H}_2\text{O}(l)$