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Ray Of Light [21]
2 years ago
10

A ball is thrown in the air from the top of a building. Its height, in meters above ground, as a function of time, in seconds, i

s given by h(t)=−4.9x2+19.6x+24.
a. How long does does it take for the ball to reach its maximum height?
b. What is the maximum height of the ball?
Mathematics
1 answer:
Cerrena [4.2K]2 years ago
5 0

Answer:

a.2s b.43.6m

Step-by-step explanation:

h(t)=−4.9t2+19.6t+24

24m = inittial possition

-4.9 t2= -1/2 g t2

19.6t=  Vo t

as the initial velocity is positive, the ball is thrown up.

the maximum height of the ball is reached when the velocity is 0

V= Vo-gt=19.6m/s-9.8m/s2 t=0

t=19.6/9.8=2s

<u>it takes 2seconds for the ball to reach its maximum height</u>

h(t)=−4.9t2+19.6t+24

h(2)=-19.6m+39.2m+24=43.6m

<u>the maximum height of the ball is 43.6m</u>

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