Calculate the area of triangle ABC with altitude CD, given A (−3, −4), B (−6, 2), C (0, 0), and D (−4, −2). a. 14 square units b
. 15 square units c. 18 square units d. 20 square units
1 answer:
Answer:
b. 15 square units
Step-by-step explanation:
We notice from the graph that AB is the hypotenuse of a right triangle 3 units wide and 6 units high. The Pythagorean theorem tells you the length of that will be ...
AB = √(3^2 +6^2) = √45 = 3√5
Similarly, altitude CD is the hypotenuse of a right triangle 4 units wide and 2 units high, so its length will be ...
CD = √(4^2 +2^2) = √20 = 2√5
The area is given by the formula ...
A = 1/2bh
A = 1/2(3√5)(2√5) = 15 . . . square units
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Step-by-step explanation:
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Answer:
The sum of all positive integers is
5 + 6 + 7 + 8 + 9 + 10
= <em>45</em>
Step-by-step explanation:
Because and
So positive numbers between 4.9 and 10.09 are
<em>5+6+7+8+9+10 = 45</em>
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<em>Brainliest will be appreciated.</em>