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Eduardwww [97]
1 year ago
6

Which of the following elements would require the most energy to

Chemistry
1 answer:
umka2103 [35]1 year ago
8 0

Option D:  Chromium would require the most energy to convert one mole of gaseous atoms into gaseous ions each carrying two positive charges.

<h3>What does the term “ionization energy” mean? </h3>

The ionization energy measures an element’s ability for participating in any chemical processes that calls up for the creation of ions or the donation of other electrons.

It is defined as the energy that any electron present in a gaseous atom or ion has in order to absorb so that it comes out of the influence of the nucleus and hence freely move

Ionization energy is also said as the minimum energy required to remove the most loosely bound electron that is present in an isolated gaseous atom or a positive ion or a molecule.

It can be easily connected to the type of chemical bonds that exist between the components in the compounds that they form.

<h3>Which element ionizes most energetically?</h3>

Helium, because it has the highest first ionization energy, whereas francium has one of the lowest.

To know more about Ionization energy visit:

brainly.com/question/1602374

#SPJ9

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What is the difference in mesomeric and electromeric effect​
Leya [2.2K]

Cause their are both have difference s

8 0
3 years ago
In a 71.4 g sample of nahco 3 3 ​ , how many grams of sodium are present?
sweet [91]

There are 19.5 g Na in 71.4 g NaHCO₃

Calculate the <em>molecular mass of NaHCO₃</em>.

1 Na = 1 × 22.99 u = 22.99   u

1 H   = 1 × 1.008 u =    1.008 u

1 C   = 1 × 12.01  u =  12.01    u

3 O = 3 × 16.00 u =  <u>48.00  u </u>

               TOTAL =  84.008 u

So, there are 22.99 g of Na in 84.008 g NaHCO₃.

∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na

4 0
3 years ago
Determine the vapor pressure (atm) of rubbing alcohol (isopropanol) at 20.0 °C. The normal boiling point of isopropanol is 82.3
jeyben [28]
Here we apply the Clausius-Clapeyron equation:
ln(P₁/P₂) = ΔH/R x (1/T₂ - 1/T₁)

The normal vapor pressure is 4.24 kPa (P₁)
The boiling point at this pressure is 293 K (P₂)
The heat of vaporization is 39.9 kJ/mol (ΔH)
We need to find the vapor pressure (P₂) at the given temperature 355.3 K (T₂)

ln(4.24/P₂) = 39.9/0.008314 x (1/355.3 - 1/293)
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8 0
3 years ago
What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100g of the substance increases in te
Ierofanga [76]

Answer:

0.417 J/gºC

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature (ΔT). This can be obtained as follow:

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 70 – 10

Change in temperature (ΔT) = 60 °C

Finally, we shall determine the specific heat capacity of the substance as follow:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 100 × C × 60

2500 = 6000 × C

Divide both side by 6000

C = 2500 / 6000

C = 0.417 J/gºC

Therefore, the specific heat capacity of substance is 0.417 J/gºC

5 0
3 years ago
What happens to the particles in a substance as it freezes?
Ierofanga [76]

they move around and eventually come and join to make a solid

8 0
4 years ago
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