B D and E. C isn't the answer because it is stopped.
Based on the data provided, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.
<h3>What is the moles of calcium carbonate in 1.505 × 10^23 atoms of calcium carbonate?</h3>
The mole of a substance can be calculated as follows:
- Moles of substance = number of particles/6.02 × 10^23
Moles of calcium carbonate = 1.505 × 10^23/6.02 × 10^23
Moles of calcium carbonate = 0.25 moles
The mass of calcium carbonate in 0.25 moles is calculated as follows:
- mass = moles × molar mass
molar mass of a calcium carbonate = 100 g/mol
mass of calcium carbonate = 0.25 × 100 = 25 g.
Therefore, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.
Learn more about molar mass and mass at: brainly.com/question/15476873
Answer:
Blue Jay is the correct answer.
Explanation:
Answer:
The answer is
<h2>0.307 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of box is 345 g
volume = 1125 cm³
The density of the object is
We have the final answer as
<h3>0.307 g/cm³</h3>
Hope this helps you
