The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C
R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m
Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:
Substitute numerical values:
The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.
As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).
Learn more about Gaussian sphere here:
brainly.com/question/2004529
#SPJ4
Answer:
F= 403429 kpa
Explanation:
Pressure is the product of force and area
Mathematically,
P=F*A -------where F is force and A is area.
A= 40 *0.1 = 4mm² -----convert to m²
A= 4e⁻⁶ m²
P= 4000000 pa
F= P/A = 4000000/4e⁻⁶
F= 403428793.493 pa
F= 403429 kpa
Answer:
a) 9.0
Explanation:
The force between two point charges, obeys Coulomb's Law, which can be written as follows:
As it can be seen, if the separation between the charges remains the same, the new value of the force will be directly proportional to the product of the charges.
If both charges are tripled, the mutual force between them will be changed in a factor equal to 3.0*3.0 = 9.0
Explanation:
To determine whether something is living or nonliving, a living thing must meet seven specific characteristics: feeding, movement, respiration, excretion, growth, sensitivity, and reproduction. A living organism needs to be able to feed to make energy and grow.
Please allow me to know if I helped with a thank you, rating or brainly.
Miss Hawaii
Answer:
The person's ear canal length is 2.91 cm.
Explanation:
Given that,
Frequency = 3000 Hz
Temperature = 30°C
We need to calculate the speed
Using equation of sound wave with temperature
[texs]v(t)=331+0.6\times T[/tex]
Put the value of T
We need to calculate the length
Using formula of closed organ pipe
Where, L = length
v = velocity
f = frequency
Put the value into the formula
Hence, The person's ear canal length is 2.91 cm.
