<h3>Derivation of Conservation of Momentum</h3>
Applying Newton's third law, these two impulsive forces are equal and opposite i.e. If the time of contact is t, the impulse of the force F21 is equal to the change in momentum of the first object. The impulse of force F12 is equal to the change in momentum of the second object.
<h2>MARK ME BRAINLIST</h2>
Answer:
The strength of an electromagnet can be increased by increasing the number of loops of wire around the iron core and by increasing the current or voltage. You can make a temporary magnet by stroking a piece of iron or steel (such as a needle) along a permanent magnet.
There are three things that dictate how strong this field is:
1.How much kinetic energy you provide the wire
Answer is changed by pushing more current through the wire.
2. How permeable our magnetic rod is
Answer is changed by picking a more magnetic media
3.How many little magnetic fields you generate to make the net, large magnetic field
Answer is changed by increasing the amount of turns of the wire. More turns, more little fields, strong big field
Answer: Using fuel that has a lower-than-specified fuel rating.
Explanation:
Most likely, what causes the cylinder head temperature and engine oil temperature gauges to exceed their normal operating ranges is using fuel that has a lower-than-specified fuel rating. This can lead to detonation of the engine which is the tendency for the fuel to pre-ignite or auto-ignite in an engine's combustion chamber.The cylinder head and the engine oil are part of the automobile systems that helps in fuel combustion.
Question: Initially, the car travels along a straight road with a speed of 35 m/s. If the brakes are applied and the speed of the car is reduced to 13 m/s in 17 s, determine the constant deceleration of the car.
Answer:
1.29 m/s²
Explanation:
From the question,
a = (v-u)/t............................ Equation 1
Where a = deceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.
Given: v = 13 m/s, u = 35 m/s, t = 17 s.
a = (13-35)/17
a = -22/17
a = -1.29 m/s²
Hence the deceleration of the car is 1.29 m/s²
Answer:
past and past participle of catch.