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Alenkinab [10]
3 years ago
9

As object has a charge of 4.5 c. did it gain or lose electrons

Physics
1 answer:
Tanya [424]3 years ago
3 0
The object lost electrons because one electron adds a negative to the object. <span />
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The Type K thermocouple has a sensitivity of about 41 uV /°C, i.e. for each degree difference in the junction temperature, the o
Novosadov [1.4K]

Answer:

ΔTmin = 3.72 °C

Explanation:

With a 16-bit ADC, you get a resolution of 2^{16}=65536 steps. This means that the ADC will divide the maximum 10V input into 65536 steps:

ΔVmin = 10V / 65536 = 152.59μV

Using the thermocouple sensitiviy we can calculate the smallest temperature change that 152.59μV represents on the ADC:

\Delta Tmin = \frac{\Delta Vmin}{41 \mu V/C}= 3.72 C

3 0
3 years ago
Suppose the carts collided on a surface that had a slight incline to it. Would you expect the momentum to be conserved
lesantik [10]

Momentum is conserved when carts are collided on a slanting plane.

To find the answer, we need to know about the conversation of momentum.

<h3>What's the conversation of momentum?</h3>
  • Conservation of linear momentum says the total momentum before the collision and after the collision remains the same.
  • Mathematically, m1u1+m2u2 = m1v1+m2v2
<h3>How is the momentum conserved when collision occurs on a slanting plane?</h3>
  • On a slanting plane, the velocity has two components,
  1. horizontal component
  2. horizontal component Vertical component
  • So, its momentum has also similar two components.
  • The momentum is conserved along horizontal direction and vertical direction separately.

Thus, we can conclude that the momentum is conserved when carts are collided on a slanting plane.

Learn more about the conversation of momentum here:

brainly.com/question/7538238

#SPJ4

7 0
1 year ago
What is the primary visible color of an emission nebula?
zzz [600]
In emission nebulae, there are interstellar clouds of hydrogen, which glow red because of the intense radiation of hot stars inside the nebula
7 0
3 years ago
Calculate the strength and direction of the electric field 300 mm to the right of a -200 C electric
Norma-Jean [14]

Answer: -1.91*10^13 v/m

Explanation:

6 0
3 years ago
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
fgiga [73]

Answer: 107.8\ J

Explanation:

Given

Initial position of object is (4.4 i+5 j)

Final position of object is (11.6 i -2 j)

Force acting (4i-9j)

Work done is given by

\Rightarrow W=F\cdot dx\\\Rightarrow W=(4i-9j)\cdot (11.6i-4.4i-2j-5j)\\\Rightarrow W=(4i-9j)\cdot (7.2i-7j)\\\Rightarrow W=28.8+63\\\Rightarrow W=91.8\ J

Initial kinetic energy

K_i=\dfrac{1}{2}\times 2\times 4^2\\\\K_i=16\ J

Change in kinetic energy is equal to work done by object

\Rightarrow K_f=K_i+W\\\Rightarrow K_f=16+91.8\\\Rightarrow K_f=107.8\ J

5 0
3 years ago
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