The answer is 267.93 g
Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol
The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%
Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
Yes, it is possible to go do because it would be 2 stacks of 6
The volume of the balloon is approximately 2652 liters.
<h3>How to determine the volume occupied by the gas in a balloon </h3>
Let suppose that <em>flammable</em> hydrogen behaves ideally. GIven the molar mass (
), in kilograms per kilomole, and mass of the gas (
), in kilograms. The volume occupied by the gas (
), in cubic centimeters, is found by the equation of state for <em>ideal</em> gases:
(1)
Where:
- Ideal gas constant, in kilopascal-cubic meters per kilomole-Kelvin.
- Temperature, in Kelvin
- Pressure, in kilopascals
If we know that
,
,
,
and
, then the volume of the balloon is:

(
)
The volume of the balloon is approximately 2652 liters.
To learn more on ideal gases, we kindly invite to check this verified question: brainly.com/question/8711877