Answer:
½O 2 + 2e - + H 2O → 2OH.
Explanation:
Redox reactions - Higher
In terms of electrons:
oxidation is loss of electrons
reduction is gain of electrons
Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:
iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-
oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-
iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-
If the battery was removed, the energy produced by the battery would not be able to continue its path along the circuit.
Answer:
n = 2.1 mol
Explanation:
Given data:
Number of moles of gas = ?
Volume of gas = 56.3 L
Pressure of gas = 0.899 atm
Temperature of gas = 20°C (20+273 = 293 k)
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
0.899 atm × 56.3 L = n × 0.0821 atm.L/ mol.K × 293 k
50.614 atm.L = n × 24.055 atm.L/ mol
n = 50.614 atm.L / 24.055 atm.L/ mol
n = 2.1 mol
Answer:
halogen
Explanation:
group 17 contains halogens