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Natasha2012 [34]
3 years ago
7

What are the units of k in the following rate law?

Chemistry
1 answer:
Ludmilka [50]3 years ago
8 0

Answer:

B. \frac{1}{M^{2} s }

Explanation:

The unit for rate is M/s while the unit for each molecule should be M. You can find the unit for k by putting the units for rate and the molecules into the equation

rate= k{X][Y]

M/s= k * M^{2} * M^{1}

k= (M/s) / (M^{3})

k= \frac{1}{M^{2} s }

You can also use this predetermined formula to solve this problem faster: k= \frac{M^{1-n} }{s }

Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so

k= \frac{M^{1-n} }{s }

k= \frac{M^{1-3} }{s }= \frac{m^{-2}}{s}= \frac{1}{M^{2} s }

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