Question

What are the intercepts of the line

Answer 1

Answer:

$y-intercept(0,-32)\\\\x-intercept(\frac{16}{5},0)$

Step-by-step explanation:

The y-intercept happens where x is 0, and the x-intercept if where y is 0. You can use this knowledge to find the intercepts.

This equation is written in slope-intercept form:

$y=mx+b$

where b is the y-intercept, so the y-intercept is -32.

To find the x intercept, insert 0 as the value of y:

$0=10x-32$

Solve for x. Add 32 to both sides:

$0+32=10x-32+32\\\\32=10x$

Divide both sides by 10:

$\frac{32}{10}=\frac{10x}{10} \\\\x=\frac{32}{10} =\frac{16}{5}$

The x-intercept is at $\frac{16}{5}$ or $3.2$ .

Find the points:

$y-intercept(0,-32)\\x-intercept(\frac{16}{5},0)$

Finito.

Answer 2

Answer:

y intercept (0,-32)

x intercept (3.2,0)

Step-by-step explanation:

To find the y intercept set x = 0 and solve for y

y = 10x -32

y = 0-32

y = -32

(0,-32)

To find the x intercept set y = 0 and solve for x

y = 10x -32

0 = 10x -32

Add 32 to each side

32 = 10x

Divide by 10

32/10 = x

(3.2,0)