We have 60 gallons of 20% antifreeze.
How much 70% antifreeze do we add to get 60% antifreeze?
We'll make "x" the gallons of 70% we must add.
.20 * 60 + .70 x = .60 * (60 + x)
12 + .70x = 36 + .60x
.10x = 24
x = 240 gallons of 70% antifreeze.
Source
1728.com/mixture.htm (see example B)
Answer:
412in
Step-by-step explanation:
First we must get rid of the -3 in the denominator
to do this you need to multiply both sides by -3
2x - 1 <span>< -5
now add 1 to both sides
2x </span><span>< -4
finally, divide both sides by 2
x </span><span>< -2
i hope this helps !!</span>
The domain is set of x-value.
Therefore, the domain of the relation Domain of R = {3,1,-1}
(x-3)=-3x+25
Because we know that y=x-3 so we put that in place of y in the equation