The answer is B. , it will relates to its amplitude
Amplitude is the maximum extent of a vibration or oscilation , measured from the position of equilibrium.
Hope this help you out
I do, and my brother and son-in-law can also solve it.
Note: V1, V2, V3, I1, I2, and I3 are not labeled in the picture, so those can't be solved for.
Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm.?
Point a is at the center of the square, and point b is at the empty corner closest to q2. Take the electric potential to be zero at a distance far from both charges.
(a) What is the electric potential at point a due to q1 and q2?
(b) What is the electric potential at point b?
(c) A point charge q3 = -6.00 μC moves from point a to point b. How much work is done on q3 by the electric forces exerted by q1 and q2?
Answer:
a) the potential is zero at the center .
Explanation:
a) since the two equal-magnitude and oppositely charged particles are equidistant
b)(b) Electric potential at point b, v = Σ kQ/r
r = 5cm = 0.05m
k = 8.99*10^9 N·m²/C²
Q = -2 microcoulomb
v= (8.99*10^9) * (2*10^-6) * (1/√2m - 1) / 0.0500m
v = -105 324 V
c)workdone = charge * potential
work = -6.00µC * -105324V
work = 0.632 J
A compound is a substance that consists of two or more elements, which is chemically combined, meaning that it could only be split by chemical means.
Examples:-
- NaCl is salt, chemically combined of Sodium and Chloride.
- H2O is water, chemically combined of Hydrogen and oxygen.
Answer:
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
where Vf is the final velocity, Vi is the initial velocity, and t is the time.
Since the car came to a complete stop, it's final velocity was 0 meters per second.
The initial velocity was 22 meters per second.
The time was 2.0 seconds.
Substitute the values into the formula.
Subtract in the numerator first.
Divide.
The acceleration of the car was -11 meters per square second. The negative acceleration indicates slowing down/stopping.
