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bulgar [2K]
3 years ago
12

The price of stock A at 9 am was $16.15 since then the price has been increasing at the rate of $0.06 each hour at noon the pric

e of stock B was $16.90 it begins to decrease at the rage od $0.12 Each hour if the two rates continue in how many hours will the prices of two stocks be the same

Mathematics
1 answer:
Ulleksa [173]3 years ago
8 0

9514 1404 393

Answer:

  6 1/6 hours after 9 am, or 3 1/6 hours after noon

Step-by-step explanation:

If we count time (x) in hours after 9 am, the stock prices will be ...

  A = 16.15 +0.06x

  B = 16.90 -0.12(x -3)

The value of x when A = B can be found from ...

  A = B

  16.15 +0.06x = 16.90 -0.12(x -3)

  0.18x = 1.11 . . . . . . . . add 0.12x-16.15

  x = 6.16666...(repeating) = 6 1/6

6 1/6 hours after 9 am, the prices will be the same. That is 3 1/6 hours after noon.

_____

The attached graph shows the time as military time: 15.167. That's 3:10 pm, or 6 1/6 hours after 9 am.

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3 years ago
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no need for explanation

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6 0
2 years ago
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