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juin [17]
3 years ago
14

How does the efficiency of the inclined plane vary with the inclination angle?

Physics
1 answer:
svlad2 [7]3 years ago
3 0
Friction , as the angle gets huger and higher , this is less and less normal force into the inclined plane .
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How much energy is needed to melt 150 g of ice at 0°C to water? (1)(Lf =3.34˟ 10⁵ J/Kg)
NARA [144]

Answer:

5.01×10⁴ J.

Explanation:

Applying,

q = Cm....................... Equation 1

Where q = amount of heat needed to melt the ice, m = mass of the ice, C = specific latent heat of ice.

From the question,

Given: m = 150 g = (150/1000) kg = 0.15 kg, C = 3.34×10⁵ J/kg

Substitute these values into equation 1

q = (0.15×3.34×10⁵)

q = 0.501×10⁵ J

q = 5.01×10⁴ J.

5 0
3 years ago
Urgent! Based on the diagram below, what color will each pigmented paper appear to be to an observer?
Nastasia [14]

Answer:

Example A will appear green, while Example B will appear greenish-blue.

Explanation:

The color of an object depend on which part of the visible light it reflects towards the observer. Visible light is made up of seven colors: Violet, Indigo, Blue, Green, Yellow, Orange, and Red (VIBGYOR). If all the colors will be reflected object will appear white. If all the colors are absorbed the object appears black. In example A, only green color is being reflected so it will appear <em>Green</em>.

In example B, green and blue are being reflected so the object will appear a mix of green and blue. This color is cyan (greenish blue).

7 0
3 years ago
A jet liner must reach a speed of 82 m/s for takeoff. If the
SIZIF [17.4K]

Answer:

The acceleration that the jet liner that must have is 2.241 meters per square second.

Explanation:

Let suppose that the jet liner accelerates uniformly. From statement we know the initial (v_{o}) and final speeds (v_{f}), measured in meters per second, of the aircraft and likewise the runway length (d), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (a), measured in meters per square second:

a = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot d}

If we know that v_{o} = 0\,\frac{m}{s}, v_{f} = 82\,\frac{m}{s} and d = 1500\,m, then the acceleration that the jet must have is:

a = \frac{\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (1500\,m)}

a = 2.241\,\frac{m}{s^{2}}

The acceleration that the jet liner that must have is 2.241 meters per square second.

3 0
3 years ago
Which feature of a longitudinal wave corresponds to a trough in a transverse wave?
Rama09 [41]
It’s the crest, the crest is the top part of the wave and the trough is the bottom so they correspond
3 0
3 years ago
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Consumed by Fire and Brimstone would be 1 symptom of Gomorrah lol
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