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Kryger [21]
3 years ago
11

A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. Complete the following statemen

t: The centripetal acceleration of the ball can be increased by a factor of 4 by Entry field with incorrect answer keeping the radius fixed and increasing the period by a factor of 4. keeping the radius fixed and increasing the speed by a factor of 4. keeping the radius fixed and decreasing the period by a factor of 4. keeping the speed fixed and decreasing the radius by a factor of 4. keeping the speed fixed and increasing the radius by a factor of 4.
Physics
1 answer:
Eva8 [605]3 years ago
7 0

Answer:

Keeping the speed fixed and decreasing the radius by a factor of 4

Explanation:

A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. The centripetal acceleration is given by :

a=\dfrac{v^2}{R}

We need to find how the "centripetal acceleration of the ball can be increased by a factor of 4"

It can be done by keeping the speed fixed and decreasing the radius by a factor of 4 such that,

R' = R/4

New centripetal acceleration will be,

a'=\dfrac{v^2}{R'}

a'=\dfrac{v^2}{R/4}

a'=4\times \dfrac{v^2}{R}

a'=4\times a

So, the centripetal acceleration of the ball can be increased by a factor of 4.

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3 years ago
A bullet is fired straight up from a gun with a
melamori03 [73]

Answer: 815.51 m

Explanation:

This situation is related to projectile motion or parabolic motion, in which the initial velocity of the bullet has only y-component, since it was fired straight up. In addition, we are dealing with constant acceleration (due gravity), therefore the following equations will be useful to solve this problem:

V=V_{o}+gt (1)

V^{2}=V_{o}^{2}+2gy (2)

Where:

V is the final velocity of the bullet

V_{o}=152 m/s is the initial velocity of the bullet

g=-9.8 m/s^{2} is the acceleration due gravity, always directed downwards

t=6.9 s is the time

y is the vertical position of the bullet at t=6.9 s

Let's begin by finding V from (1):

V=152 m/s-9.8 m/s^{2}(6.9 s) (3)

V=84.38 m/s (4)

Now we have to substitute (4) in (2):

(84.38 m/s)^{2}=(152 m/s)^{2}-2(9.8 m/s^{2})y (5)

Isolating y:

y=815.511 m This is the displacement  of the bullet after 6.9 s

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3 years ago
A tape diagram. 0 dollars is 0 percent. Question mark dollars is 23 percent. 52 dollars is 100 percent. Jared has earned 23% of
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17.15 :)

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Read 2 more answers
The diagram shows a wave moving from one medium to another
Shtirlitz [24]

As the speed of wave decreases, the wavelength of the wave decreases.

<h3>Refraction</h3>

We know that as a wave travels from one medium to another its speed decreases depending on if the first medium is less dense than the second medium or increases depending on if the first medium is more dense than the second medium. This is known as refraction

Now, we know that the speed of a wave v = fλ where

  • f = frequency and
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The ratio of the speed in medium one to speed in medium two is called the refractive index of medium 1 to 2.

<h3>Explaining the diagram</h3>

From the diagram, we see that the wavelength in medium 1 is longer than that in medium 2. Since wavelength and speed are proportional, so the speed in medium 1 is also greater than the speed in medium 2.

So, As the speed of wave decreases, the wavelength of the wave decreases.

Learn more about refraction here:

brainly.com/question/25758484

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2 years ago
A race car starts from rest and travels east along a straight and level track. For the first 5.0 s of the car's motion, the east
son4ous [18]
The solution to your problem is as follows:

a=dv/dt=2*0.82*twhat time velocity is 13.7 solve 13.7=0.82*t^2   t=sqrt(13.7/0.82)  =4.51 sUse the time in the acceleration expression a= 2*0.82*4.51=7.39m/s^2


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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3 years ago
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