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AleksandrR [38]
3 years ago
11

If a certain gas occupies a volume of 12 l when the applied pressure is 6.0 atm , find the pressure when the gas occupies a volu

me of 3.0 l .
Physics
1 answer:
dolphi86 [110]3 years ago
5 0
From Boyle's law, the volume of a fixed mass of a gas is inversely proportional to its pressure at constant absolute temperature. 
Therefore; P1V1 =P2V2; where PV is a constant
hence; 12 × 6 = 3× p2
           p2 = 72/3
                = 24 atm
Therefore; the new pressure will be 24 atm
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What year did Badminton become a full-medal Olympic sport?
Basile [38]

Answer:

1992

Explanation:

Badminton made its debut as a demonstration sport at the 1972 Olympic Games in Munich. It was not until the 1992 Games in Barcelona that it was officially included on the Olympic programme, with men's and women's singles and doubles events.

6 0
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4. A disobedient student dropped his Physics textbook (mass 0.1kg) from the window (15m above the ground). How fast was it going
vaieri [72.5K]

Answer:

v= 17.15 m/s

Explanation:

mass of the book=0.1 Kg

height above ground, h= 15 m

Using conservation of energy

Potential energy is converted into kinetic energy

mgh = \frac{1}{2}mv^2

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 15}

v=\sqrt{294}

v= 17.15 m/s

Hence, the book will hit the ground at the speed of 17.15 m/s.

8 0
2 years ago
A person carries a plank of wood 1.6 m long with one hand pushing down on it at one end with a force F1 and the other hand holdi
Elis [28]

Answer: 115.52\ N

Explanation:

Given

Length of plank is 1.6 m

Force F_1 is applied on the left side of plank

Force F_2 is applied 43 cm from the left end O.

Mass of the plank is m=13.7\ kg

for equilibrium

Net torque must be zero. Taking torque about left side of the plank

\Rightarrow mg\times 0.8-F_2\times 0.43=0\\\\\Rightarrow F_2=\dfrac{13.7\times 9.8\times 0.8}{0.43}\\\\\Rightarrow F_2=249.78\ N

Net vertical force must be zero on the plank

\Rightarrow F_1+W-F_2=0\\\Rightarrow F_1=F_2-W\\\Rightarrow F_1=249.78-13.7\times 9.8\\\Rightarrow F_1=115.52\ N

8 0
2 years ago
In an isolated system, Bicycle 1 and Bicycle 2, each with a mass of 10 kg,
dimulka [17.4K]

Answer: 20 kgm/s

Explanation:

Given that M1 = M2 = 10kg

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Since momentum is a vector quantity, the direction of the two object will be taken into consideration.

The magnitude of their combined

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M1V1 - M2V2

Substitute all the parameters into the formula

10 × 5 - 10 × 3

50 - 30

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Therefore, the magnitude of their combined momentum before the crash will be 20 kgm/s

7 0
3 years ago
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