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Valentin [98]
3 years ago
15

Find the cube root of 216

Mathematics
2 answers:
andre [41]3 years ago
7 0
6 is the cube root of 216.

I hope this helps! :D
Shtirlitz [24]3 years ago
6 0
∛216

216 = 6 * 6 * 6

∛216 = ∛(6 * 6 * 6) = 6,

Cube root of 216 = 6
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Airplanes arrive at a regional airport approximately once every 15 minutes. If the probability of arrivals is exponentially dist
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The answer is 0.2835

Given: Airplane arrives once every 15 minutes,

So Expected duration (µ) = 15

The rate parameter (λ) = 1/µ = 1/15

What is the expected duration (µ)?

Expected duration is the duration between two events to occur.

What is the rate parameter in exponential distribution?

The rate parameter shows how quickly the decay of the exponential function occurs. It is given by the reciprocal of expected duration that is λ = 1/µ,

where λ is the rate parameter and µ is the expected duration.

Also given that the probability of arrivals is exponentially distributed.

How to find the probability for some value (x) less than for some Random variable (X) that is distributed exponentially?

The probability for some value (x) less than for some Random variable (X) is given by

P(X<x) = 1- e^(-λx),

where

X = Random variable

x = value of some given specified condition

λ = rate parameter.

In the question, "a plane arrives in less than 5 minutes" so x = 5.

Therefore,

P(X<5) = 1 - e^(-1/15.5)

= 1 – 0.716531

= 0.283469 ≈ 0.2835.

Hence, the probability that a plane arrives in less than 5 minutes is 0.2835

Learn more about "exponential probability distribution" here: brainly.com/question/22985880

#SPJ4

4 0
1 year ago
The mean age of teachers at Davis senior high school is 43.6 years. If a hypothesis test is performed, how should you interpret
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Answer:

The interpretation is

   There is not sufficient evidence to support the claim that \mu = 43.6

Step-by-step explanation:

From the question we are told that

  The population mean is  \mu =  43.6 \ years

Generally

    The null hypothesis is  H_o : \mu = 43.6

Given from the question that the null hypothesis was rejected then the conclusion will be

   There is not sufficient evidence to support the claim that \mu = 43.6

5 0
3 years ago
Stephanie and 2 friends went to Vancouver for a winter weekend. Stephanie made 7 cups of apple cider. Everyone, including, Steph
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Everyone gets equally 2 1/3 cups of apple cider
3 0
3 years ago
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Ernesto is shopping at store that is having a clearance sale. The price of everything in the store is discounted by 25%. If Earn
maksim [4K]
$17.49 because you multiply 22 by .25 getting 5.5. You subtract that from the original 22 getting 16.5 which you then multiply by the sales tax .06. Add the tax amount to the 16.5 to get 17.49.
3 0
3 years ago
A randomly selected sample of college basketball players has the following heights in inches. See Attached Excel for Data. Compu
Illusion [34]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  confidence interval is  64.86

Step-by-step explanation:

From the question we are given the following data

   The following heights are

66, 65, 67, 62, 62, 65, 61, 70, 66, 66, 71, 63, 69, 65, 71, 66, 66, 69, 68, 62, 65, 67, 65, 71, 65, 70, 62, 62, 63, 64, 67, 67      

 The  sample size is n  =32

  The confidence level is k  = 95% = 0.95

The mean is evaluated as

          \= x = 66+ 65+ 67+ 62+ 62+ 65+ 61+ 70+ 66+ 66+ 71+63+ 69+ 65+ 71+ 66+ 66+ 69+ 68+ 62+ 65+ 67,+\\65+ 71+ 65+ 70+ 62+ 62+ 63+ 64+ 67+ 67 / 32

=>   \= x = \frac{2108}{32}

=>     \= x = 65.875

The standard deviation is evaluated as

           \sigma =  \sqrt{ v}

Now  

   v = ( 66-65.875 )^2+(65-65.875)^2+( 67-65.875)^2+ (62-65.875)^2+ (62-65.875)^2+ (65-65.875)^2+( 61-65.875)^2+ (70-65.875)^2+ (66-65.875)^2+ (66-65.875)^2+ (71+63-65.875)^2+ (69-65.875)^2+ (65-65.875)^2+ (71-65.875)^2+( 66-65.875)^2+ (66-65.875)^2+ (69-65.875)^2+ (68-65.875)^2+ (62-65.875)^2+ (65-65.875)^2+ (67-65.875)^2,+\\(65-65.875)^2+ (71-65.875)^2+ (65-65.875)^2+ (70-65.875)^2+( 62-65.875)^2+( 62-65.875)^2+ (63-65.875)^2+ (64-65.875)^2+ (67-65.875)^2+ (67-65.875)^2 / 32

=>v=  8.567329

=>   \sigma  =  \sqrt{8.567329}

=>   \sigma  =  2.927

The level of significance is evaluated as

        \alpha  =  1 - 0.95

        \alpha  =  0.05

The degree of freedom is  evaluated as

    Df =  n- 1 \equiv  Df  =  32 -1 = 31

The critical values for the level of significance is obtained from the z -table as

      t_c = t_{\alpha/2 } , Df =  t _{0.05/2}, 31 =\pm 1.96

The confidence interval is evaluated as

       \mu  = \= x \pm t_c *  \frac{\sigma }{\sqrt{n} }

substituting values

        \mu =65.875 \pm 1.96* \frac{2.927}{\sqrt{32} }

       \mu =65.875 \pm 1.01415

=>    64.86

4 0
3 years ago
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