–48 ÷ 8 Show me plz.

Maggie is standing on a platform that is 8 feet above the ground. She throws a ball in the air that hits the ground after 2 seco

Paha777 [63]

The equation that offers the best approximation to this result is: $h = -16\cdot t^{2}+28\cdot t + 8$ . (Choice D)

<h3>How to find the free fall formula for a given scenario</h3>

An object experiments a free fall when it is solely accelerated by gravity on the assumption of an uniform acceleration. The formula is described below:

$h =h_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g\cdot t^{2}$ (1)

Where:

$h_{o}$ - Initial height, in feet.
$v_{o}$ - Initial speed, in feet per second.
$t$ - Time, in seconds.
$g$ - Gravitational acceleration, in feet per square second.

If we know that $t = 2\,s$ , $h_{o} = 8\,ft$ , $h = 0\,ft$ , $g = -32.174\,\frac{ft}{s^{2}}$ , then the height formula is:

$0 = 8 +2\cdot v_{o} - \frac{1}{2}\cdot (32.174)\cdot (2)^{2}$

$0 = -56.348+2\cdot v_{o}$

$v_{o} = 28.174\,\frac{ft}{s}$

The equation that offers the best approximation to this result is: $h = -16\cdot t^{2}+28\cdot t + 8$ . (Choice D)

To learn more on free fall, we kindly invite to check this verified question: brainly.com/question/13796105

5 0

2 years ago

Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1

defon

I'm guessing the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}$

By the ratio test, the series converges if the following limit is less than 1.

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|$

The first $n$ terms in the numerator's denominator cancel with the denominator's denominator:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|$

$|x^n|$ also cancels out and the remaining factor of $|x|$ can be pulled out of the limit (as it doesn't depend on $n$ ).

$\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0$

which means the series converges everywhere (independently of $x$ ), and so the radius of convergence is infinite.

3 0

3 years ago

What is 7 times the sum of a squared and b minus 4 times the sum of a squared and b

spayn [35]

The sum of a squared and b is given by
$a^2+b$

7 times the sum of a squared and b is given by
 $7(a^2+b)$
while 4 times the sum of a squared and b is given by
 $4(a^2+b)$

Therefore, 7 times the sum of a squared and b minus 4 times the sum of a squared and b is given by

$7(a^2+b)-4(a^2+b)=3(a^2+b)$

7 0

3 years ago

Which ordered pairs could be points on a line parallel to the line that contains (3, 4) and (–2, 2)? Check all that apply.

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

As we go from (–2, 2) to (3, 4), x increases by 5 and y increases by 4. Thus, the slope of the line through (–2, 2) and (3, 4) is

m = rise / run = 4/5.

Use the slope-intercept form of the equation of a straight line:

y = mx + b becomes 4 = (4/5)(3) + b. Multiplying all three terms by 5, we eliminate the fraction: 20 = 12 + b. Thus, b = 8, and the equation of the line through (–2, 2) and (3, 4) is y = (4/5)x + 8.

A line parallel to this one would have the form y = (4/5)x + b; note that the slopes of these two lines are the same, but the y-intercept, b, would be different if the two lines do not coincide.

Unfortunately, you have not shared the ordered pairs given in this problem statement.

You could arbitrarily let b = 0. Then the parallel line has equation

y = (4/5)x; if x = 3, then y = (4/5)(3) = 12/5, and so (3, 12/5) lies on the parallel line.

3 0

3 years ago

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An isosceles right triangle has 30 degree angles in its interior. B. False A. True

Margarita [4]

False, an iso triangle has 2 equal sides like an icecream cone but are not limited to 30 degrees all the time.

7 0

3 years ago

Read 2 more answers