There are 
ways of picking 2 of the 10 available positions for a 0. 8 positions remain.
There are 
ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's 
way of doing that.
So we have
The last expression has a more compact form in terms of the so-called multinomial coefficient,
Answer:
11in
Step-by-step explanation:
a^2+b^2=c^2 when c is the hypotenuse
10^2+sqrt21^2=c^2
100+21=c^2
121=c^2
11=c
9514 1404 393
Answer:
C. 3√2 units
Step-by-step explanation:
The diagonal of a square is √2 times the side length. For a square with side length 3, the diagonal is 3√2.
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If you like, you can see this using the Pythagorean theorem.
d² = s² + s² . . . . . where d is the diagonal, and s is the side
d² = 2s²
d = √(2s²) = s√2
For s=3, ...
d = 3√2
The answere is 213 boxes
If you add 3 dozens to 14 dozens of boxes of envilopes , then you get 17 dozens of boxes of envilopes.Then of you sum up the 1/2 (2/4 ) with the 1/4.You get 3/4. Finally, you add 17 dozens to 3/4 of a dozen you get 17 3/4 dozens( wich is 213 boxes )
