Answer : The mass of dissolved will be, 0.2365 grams
Explanation :
First we have to calculate the concentration of .
As we know that,
where,
= concentration of = ?
= partial pressure of = 1.65 atm
= Henry's law constant =
Now put all the given values in the above formula, we get:
The concentration of =
Now we have to calculate the moles of
Now we have to calculate the mass of
Therefore, the mass of dissolved will be, 0.2365 grams
Given:
pH is 5.27
Concentration of sol'n 0.013m (weak monoprotic)
Determine H+ concentration:
[H+] = 10^-pH
= 10^-5.27
= 5.37x10^-6
Ka = [H+] [A-] / [HA]
= (5.37x10^-6) * (5.37x10^-6) / (0.013 - 5.37x10^-6)
= 2.22x10^-9
The answer to this question is a
Answer:
CH₃CO₂H + H₂O ⇄ CH₃CO₂⁻ + H₃O⁺
Explanation:
A buffer is defined as the mixture of a weak acid and its conjugate base or vice versa.
For the acetic acid buffer, CH₃CO₂H is the weak acid and its conjugate base is the ion without H⁺, that is CH₃CO₂⁻. The equilibrium equation in water knowing this is:
<h3>CH₃CO₂H + H₂O ⇄ CH₃CO₂⁻ + H₃O⁺</h3>
<em>In the equilibrium, the acid is dissociated in the conjugate base and the hydronium ion.</em>