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HACTEHA [7]
4 years ago
7

WaNnA Be BRaINleSt; A satellite was in two separate crashes. In both crashes, the satellite had the same mass. Engineers want to

know about the speed and direction of the satellite after the crashes. Why would the crash affect the motion of the satellite, and which crash caused a greater change in motion for the satellite?
Chemistry
1 answer:
mr Goodwill [35]4 years ago
3 0

Answer:

Explanation:

D

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What happens when you mix hydrogine, potassium and sodium
Anika [276]

Answer:

-

Explanation:

As the piece of metal skitters across the surface of the water in a beaker and — particularly in the case of potassium — it appears to catch fire, it is not obvious that the explanation for both phenomena lies in the production of hydrogen gas.

3 0
3 years ago
Hydrazine (N2H4) is used as rocket fuel. It reacts with oxygen to form nitrogen and water.
Marina86 [1]

Answer:

See explanation below for answers

Explanation:

This is a stochiometry reaction. LEt's write the overall reaction again:

N₂H₄ + O₂ ---------> N₂ + 2H₂O

This reaction is taking place at Standard temperature and pressure conditions (STP) which are P = 1 atm and T = 273 K.  To know the volume of N₂ formed, we need to know first how many moles are formed, and this can be calculated with the reagents and the limiting reagent. Let's calculate the moles first of the reagents:

MM N₂H₄ = 32 g/mol;    MM O₂ = 32 g/mol

mol N₂H₄ = 2000 / 32 = 62.5 moles

mol O₂ ? 2100 / 32 = 65.63 moles

Now that we have the moles, we need to apply the stochiometry and calculate the limiting reagent. According to the overall reaction we have a mole ratio of 1:1 between N₂H₄ and O₂, therefore:

1 mole N₂H₄ ---------> 1 mole O₂

62.5 moles ----------> X

X = 62.5 moles of O₂

But we have 65.63 moles, therefore, the limiting reactant is the N₂H₄.

We also have a 1:1 mole ratio with the N₂, so:

moles N₂H₄ = moles N₂ = 62.5 moles

Now that we have the moles, we can calculate the volume with the ideal gas equation:

PV = nRT

V = nRT / P

R: gas constant (0.082 L atm / K mol)

Replacing we have:

v = 62.5 * 0.082 * 273 / 1

V = 1399.13 L of N₂

Now, how many grams of the excess remains?, we know how many moles are reacting so, let's see how much is left:

moles remaining = 65.63 - 62.5 = 3.12 moles

then the mass of oxygen:

m = 3.12 * 32 = 100.16 g of O₂

7 0
3 years ago
Read 2 more answers
Give the hybridization for the c in hcch. group of answer choices
Tamiku [17]

The hybridization for C in acetylene, HCCH, or C₂H₂ is 'sp'.

Discussion:

There are three different forms of hybridization -

  1. sp- The first occurs when two carbon atoms are triple linked.
  2. sp₂- When two carbon atoms are double-bonded to one another, this is known as sp₂.
  3. sp₃- When a single bond joins two carbon atoms, this is known as sp₃.

In the case of acetylene(HCCH or C₂H₂):

  • The carbon atom requires additional electrons to establish four bonds with hydrogen and other carbon atoms in the synthesis of C₂H₂. One 2s₂ pair is consequently transferred to the vacant 2pz orbital. Each carbon has two sp hybrid orbitals after the 2s orbital in each atom combines with one of the 2p orbitals.
  • As a result of the atoms' symmetrical alignment in a single plane, C₂H₂ possesses a linear molecular structure. Due to their lower electronegative nature than Hydrogen atoms, all Carbon atoms are situated near the center of the Lewis structure of C₂H₂.

                                              H-C≡C-H

Therefore, it is concluded from the above discussion that the hybridization type of acetylene is 'sp'.

Learn more about hybridization here:

brainly.com/question/14140731

#SPJ4

5 0
2 years ago
What is the empirical formula of a molecule containing 65.5% carbon, 5.5% hydrogen, and 29.0% oxygen?
rusak2 [61]

Answer:

The empirical formula is C3H3O

Explanation:

Step 1: Data given

Suppose the mass of the molecule = 100 grams

The molecule contains:

65.5 % Carbon = 65.5 grams

5.5 % Hydrogen = 5.5 grams

29.0% Oxygen = 29.0 grams

Molar mass of C = 12 g/mol

Molar mass of H = 1.01 g/mol

Molar mass of O = 16 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles C = 65.5 grams / 12 g/mol = 5.46 moles

Moles H = 5.5 / 1.01 g/mol = 5.45 moles

Moles O = 29.0 grams / 16 g/mol = 1.8125 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

C: 5.46 / 1.8125 = 3

H = 5.45 / 1.8125 = 3

O = 1.8125/1.8125 = 1

The empirical formula is C3H3O

8 0
3 years ago
How do electrostatic forces affect the electrons in an atom?
kkurt [141]
The answer is C.
Electrostatic force binds the the negatively charged to the positive charge atomic nucleus
3 0
2 years ago
Read 2 more answers
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