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kupik [55]
3 years ago
12

If the velocity of a car is 45 km/h west, how far can it travel in 0.5 hours?

Physics
2 answers:
Anarel [89]3 years ago
6 0
45km/h * 0.5h= 22.5km

The car can travel 22.5km in 0.5 hours
Dominik [7]3 years ago
6 0

(45 km/hour west) · (0.5 hour) =

(45 · 0.5) · (km · hour west/hour) =

22.5 km west

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ivolga24 [154]

Answer:

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50.0 / 9.5 = 5.26 s

25.0 / 11.1 = 2.25 s

T (Wood) = 2.5 + 5.26 + 2.25 = 10.0 s

Mrs Wood runs 10 s vs 10.4 for Mr Overstreet

7 0
3 years ago
A force is applied to an ideal spring (initially in its equilibrium position) and does 1.9 JJ of work stretching it 2.2 cmcm . H
Verdich [7]

Answer:

W=16.58J

Explanation:

initial information we have

work: W=1.9J

stretched distance: x=2.2cm=0.022m

from this, we can find the value of the constant of the spring k, with the equation for work in a spring:

W=\frac{1}{2} kx^2

substituting known values:

1.9J=\frac{1}{2}k(0.022)^2\\

and clearing for k:

k=\frac{2(1.9J)}{0.022^2} \\k=7,851.24

and now we want to know how much work is done when we stretch the spring a distance of 6.5cm from equilibrium, so now x is:

x=6.5cm=0.065m

and using the same formula for work, with the value of k that we just found:

W=\frac{1}{2} kx^2

W=\frac{1}{2}(7851.24)(0.065)^2\\W=16.58J

5 0
3 years ago
Read 2 more answers
Which is belief held by sociologists who work from a social-conflict perspective
Ksju [112]
Some social patterns are helpful, while others are harmful.
7 0
4 years ago
Read 2 more answers
Identify each statement as an example of melting or sublimation,
xeze [42]

1st is sublimation

2and is melting

3red is melting

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5 0
3 years ago
You hold a ruler that has a charge on its tip 6 cm above a small piece of tissue paper to see if it can be picked up. The ruler
scZoUnD [109]

Answer:

q=1.4*10^{-9}C

Explanation:

Given data:

charge on ruler = -14μC

Mass of tissue is 5 g

To Know the minimum charge,  equate electrostatic force to weight  

we have F = W

so\frac{KQq}{r^2} =mg

putting all value in equation,

=\frac{9*10^9*(14*10^{-6})*q}{0.06^2} = 5* 10^{-3}*9.8

solving for q

q =\frac{5* 10^{-3}*9.8 *0.06^2}{9*10^9*(14*10^{-6})}

or q=1.4*10^{-9}C

5 0
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