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siniylev [52]
3 years ago
9

6) A person with mass 50.0 kg, standing still, throws an object with mass 12.0

Physics
1 answer:
matrenka [14]3 years ago
6 0

Explanation:

Momentum before = momentum after

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(50.0 kg) (0 m/s) + (12.0 kg) (0 m/s) = (50.0 kg) (2.0 m/s) + (12.0 kg) v

v = -8.33 m/s

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What is the difference between kinetic and potential energy and how do they work?
Iteru [2.4K]

To explain, I will use the equations for kinetic and potential energy:

PE = mgh\\KE = \frac{1}{2}mv^{2}

<h3>Potential energy </h3>

Potential energy is the potential an object has to move due to gravity.  An object can only have potential energy if 1) <u>gravity is present</u> and 2) <u>it is above the ground at height h</u>.  If gravity = 0 or height = 0, there is no potential energy.  Example:

An object of 5 kg is sitting on a table 5 meters above the ground on earth (g = 9.8 m/s^2).  What is the object's gravitational potential energy?  <u>(answer: 5*5*9.8 = 245 J</u>)

(gravitational potential energy is potential energy)

<h3>Kinetic energy</h3>

Kinetic energy is the energy of an object has while in motion.  An object can only have kinetic energy if the object has a non-zero velocity (it is moving and not stationary).  An example:

An object of 5 kg is moving at 5 m/s.  What is the object's kinetic energy?  (<u>answer: 5*5 = 25 J</u>)

<h3>Kinetic and Potential Energy</h3>

Sometimes, an object can have both kinetic and potential energy.  If an object is moving (kinetic energy) and is above the ground (potential), it will have both.  To find the total (mechanical) energy, you can add the kinetic and potential energies together.  An example:

An object of 5 kg is moving on a 5 meter table at 10 m/s.  What is the objects mechanical (total) energy?  (<u>answer: KE = .5(5)(10^2) = 250 J; PE = (5)(9.8)(5) = 245 J; total: 245 + 250 = 495 J</u>)

7 0
3 years ago
Eating 2500 Cal every day a friend of mine maintains a stable weight of 70 kg. One day, after eating 3500 Cal, he decided to do
Kaylis [27]

Answer:

Explanation:

Calories to be burnt = 3500 - 2500 = 1000 Cals .

Efficiency of conversion to mechanical work  is 25 % .

Work needed to burn this much of Cals = 1000 x 100 / 25 = 4000 Cals.

4000 Cals = 4.2 x 4000 = 16800 J  .

Work done in one jump = kinetic energy while jumping

= 1/2 m v²

= .5 x 70 x 3.3²

= 381.15 J .

Number of jumps required = 16800 / 381.15

= 44 .

4 0
2 years ago
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
OlgaM077 [116]

Answer:

On moon time period will become 2.45 times of the time period on earth

Explanation:

Time period of simple pendulum is equal to T=2\pi \sqrt{\frac{l}{g}} ....eqn 1 here l is length of the pendulum and g is acceleration due to gravity on earth

As when we go to moon, acceleration due to gravity on moon is \frac{1}{6} times os acceleration due to gravity on earth

So time period of pendulum on moon is equal to

T_{moon}=2\pi \sqrt{\frac{l}{\frac{g}{6}}}=2\pi \sqrt{\frac{6l}{g}} --------eqn 2

Dividing eqn 2 by eqn 1

\frac{T_{moon}}{T}=\sqrt{\frac{6l}{g}\times \frac{g}{l}}

T_{moon}=\sqrt{6}T=2.45T

So on moon time period will become 2.45 times of the time period on earth

5 0
3 years ago
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