How many g of N in 2.76 g Al(NO3)3
1 answer:
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Answer:
Explanation:
According to the law of mass action:-
The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.
Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.
The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.
From the reaction given that:-
The expression for the rate is:-
Given that;- k= /Ms
[P] = M
Thus,
Answer:
The absolute uncertainty is approximately 1.69 × 10⁻³
Explanation:
The volume needed for NaOH needed to make the solution = 16.66 ml
The wt% of the added NaOH = 53.4 wt%
The volume of the NaOH to be prepared = 2.00 L
The concentration of the NaOH to be prepared = 0.169 M
The molar mass of NaOH = 39.997 g/mol
Therefore, 100 g of sample contains 53.4 g of NaOH
The mass of the sample = 16.66 × 1.52 = 25.3232 g
The mass of NaOH in the sample = 0.534 × 25.3232 = 13.5225888 g ≈ 13.52 g
Therefore;
The number of moles of NaOH = 13.52/39.9971 = 0.3381 moles
Therefore, we have 0.3381 moles in 2.00L solution, which gives;
The number of moles per liter = 0.3881/2 = 0.169045 moles/liter
The molarity ≈ 0.169 M
The absolute uncertainty, u(c) is given as follows;
The absolute uncertainty, u(c) ≈ 1.69 × 10⁻³.