A train left a station at noon, travelling at 40 mph. A second train left at the station at 3 PM traveling at 60 mph. At what ti
me will the second train catch up with the first
2 answers:
Answer:
9:00 pm
Explanation:
hope it helps
Answer:
both train meet at 9.00 pm
Explanation:
let t is the time after 1st train start
we know distance = time * speed
D_1 = 40*t
D_2= 60*(t-3) ( as second train depart after 3hr gap)
we know
distance by one train = distance traveled by 2nd train i.e
D_1 = D_2
40*t=60*(t-3)
40*t = 60*t - 60*3
20*t = 180
t = 9
hence both train meet at 9.00 pm
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hope it's helps you ....
Answer:
juz taking points nvm no sry for u cos u too wasted point
