Answer:
-34.3m/s
Explanation:
first lets find the time befor it hit the ground by using free fall equation and we know we use that in one condition which is a constant acceleration in this case its a gravitational acceleration which is -9.8
![h = \frac{1}{2} g {t}^{2}](https://tex.z-dn.net/?f=h%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20g%20%7Bt%7D%5E%7B2%7D%20)
![t = \sqrt{ \frac{2 \times 60}{9.8 } } = 3.5s](https://tex.z-dn.net/?f=t%20%3D%20%20%20%5Csqrt%7B%20%5Cfrac%7B2%20%5Ctimes%2060%7D%7B9.8%20%7D%20%7D%20%20%20%3D%203.5s)
now we know that the initial velocity its zero :
so applu the another kinematic equation which is
![v = u - gt](https://tex.z-dn.net/?f=v%20%3D%20u%20-%20gt)
v is final velocity and u is the initial velocity and its equal zero.
v = - 9.8 × 3.5 = - 34.3
For Science fair project you can do convection current
Explanation:
Show how to do the process
and then make a model to demonstrate
Materials required:
Potassium Permanganate,beaker,bunsen burner,water and retort stand
C.) Friction.
Reason:
No force is opposing the motion of an object except frictional force. Hence an object requires 15 N of force to set an object in motion and is greater than friction. Hope this helps, have a great day ahead!
Answer:
![\frac{1}{2}\frac{(M_dV_0)^2}{(M_d+M_a)^2} = h](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%28M_dV_0%29%5E2%7D%7B%28M_d%2BM_a%29%5E2%7D%20%3D%20h)
Explanation:
First, we will use conservation of the linear momentum:
so:
![M_dv_0 = (M_d+M_a)V_s](https://tex.z-dn.net/?f=M_dv_0%20%3D%20%28M_d%2BM_a%29V_s)
where
is the mass of the dart,
is the speed of the dart just before it strickes the apple,
the mass of the apple and
the velocity of the apple and the dart after the collition.
Then, solving for V_s:
![V_s = \frac{M_dV_0}{M_d+M_a}](https://tex.z-dn.net/?f=V_s%20%3D%20%5Cfrac%7BM_dV_0%7D%7BM_d%2BM_a%7D)
now, using the conservation of energy:
![E_i = E_f](https://tex.z-dn.net/?f=E_i%20%3D%20E_f)
so:
![\frac{1}{2}(M_d+M_a)V_s^2 = (M_a+M_d)gh](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28M_d%2BM_a%29V_s%5E2%20%3D%20%28M_a%2BM_d%29gh)
where g is the gravity and h how high does the apple move upward.
Now, replacing
and solving for h, we get:
![\frac{1}{2}(M_d+M_a)(\frac{M_dV_0}{M_d+M_a})^2 = (M_a+M_d)h](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28M_d%2BM_a%29%28%5Cfrac%7BM_dV_0%7D%7BM_d%2BM_a%7D%29%5E2%20%3D%20%28M_a%2BM_d%29h)
![\frac{1}{2}\frac{(M_dV_0)^2}{(M_d+M_a)^2} = h](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%28M_dV_0%29%5E2%7D%7B%28M_d%2BM_a%29%5E2%7D%20%3D%20h)
Answer:
The correct answer is B)
Explanation:
When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel. So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.
The formula for calculating the velocity of a point on the edge of the wheel is given as
= 2π r / T
Where
π is Pi which mathematically is approximately 3.14159
T is period of time
Vr is Velocity of the point on the edge of the wheel
The answer is left in Meters/Seconds so we will work with our information as is given in the question.
Vr = (2 x 3.14159 x 1.94m)/2.26
Vr = 12.1893692/2.26
Vr = 5.39352619469
Which is approximately 5.39
Cheers!