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3 years ago

A neutron star has a mass of between 1.4-2.8 solar masses compressed to the size of:

Physics

1 answer:

BARSIC [14]3 years ago

7 0

The correct answer is D. An average city

Explanation:

A neutron star differs from others due to its massive density, this means a lot of matter is compressed in a small area. Indeed, neutron stars have a mass of around 1.4 to 2.8 times the mass of the sun. But these are considerably small as they only measure around 20 kilometers, which is the size of an average city. Additionally, neutron stars are this dense because they are the result of a regular star exploding, which leads to a super-dense core, or neutron star. In this context, the mass of a neutron star is compressed to the size of an average city.

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A monochromatic light passes through a narrow slit and forms a diffraction pattern on a screen behind the slit. As the slit widt

maw [93]

Answer:

shrinks with all the fringes getting narrower

Explanation:

As the light passes through the slit, the diffraction pattern shrinks, as the waves have more opening to penetrate, and the fringes becomes more narrow as a result of that, The opposite happens as the conditions are reversed.

8 0

3 years ago

. What is the relationship between potential energy, kinetic energy, and speed as the skater moves down and up the U-shaped ramp

kykrilka [37]

Top of the U ramp: potential energy is the highest, while kinetic energy is the lowest

Bottom of the U ramp(aka the curve part): potential energy is the lowest and the kinetic energy is the highest

THEREFORE, PE and KE have an INVERSE RELATIONSHIP.

6 0

3 years ago

Read 2 more answers

Increasing the number of loops in a electromagnet or solenoid will cause it to be stronger

Zielflug [23.3K]

True

The electromagnet will become stronger if we add more coils because there are more field lines in a loop then there is in a straight piece of wire. In a solenoid there are a lot of loops and they are concentrated in the middle, as more loops are added the field lines get larger, therefore making the electromagnet stronger.

5 0

3 years ago

a 5kg block on a rough horizontal surface is attached to a light spring (force constant=1.6kN/m). the block passes through its e

natima [27]

Answer:

2.12 J

Explanation:

Initial kinetic energy = final elastic energy + work by friction

KE = EE + W

KE = ½ kx² + W

5 J = ½ (1600 N/m) (0.06 m)² + W

W = 2.12 J

5 0

3 years ago

Una cuerda de 20 pies se estira entre dos arboles. Un peso W cuelga del centro de la cuerda hace que el punto medio de la misma

Galina-37 [17]

Answer:

La magnitud de la masa del peso es 78.447 libras-masa.

Explanation:

La tensión es una fuerza de reacción de la cuerda causada por la acción de una fuerza externa. En este caso, esa fuerza externa es el peso que cuelga en el centro de la cuerda. Abajo hemos adjuntado una representación simplificada del enunciado.

Por las leyes de Newton, tenemos la siguiente ecuación de equilibrio conformada por tres fuerzas:

$\vec T_{1} + \vec T_{2} + \vec W = (0, 0)\, [N]$ (1)

Donde:

$\vec T_{1}$ , $\vec T_{2}$ - Tensiones a cada lado de la cuerda, en newtons.

$\vec W$ - Peso, en newtons.

Si sabemos que $\vec T_{1} = T\cdot (\cos \alpha, \sin \alpha)$ , $\vec T_{2} = T\cdot (-\cos \alpha, \sin \alpha)$ y $\vec W = W\cdot (0, -1)$ , entonces tenemos la siguiente ecuación vectorial:

$T\cdot (\cos \alpha, \sin \alpha) + T\cdot (-\cos\alpha, \sin \alpha) + W\cdot (0, -1) = (0,0)$

$T\cdot (0, 2\cdot \sin \alpha) = W\cdot (0, 1)$

Esto permite reducir la anterior expresión a una fórmula escalar:

$2\cdot T\cdot \sin \alpha = W$

Donde $\alpha$ es el ángulo de inclinación de la cuerda, medido en grados sexagesimales.

El ángulo de inclinación de la cuerda se determina mediante la siguiente fórmula trigonométrica inversa es:

$\alpha = \tan^{-1} \left(\frac{2\,ft}{10\,ft}\right)$

$\alpha \approx 11.310^{\circ}$

Si conocemos que $\alpha \approx 11.310^{\circ}$ y $T = 200\,lbf$ , entonces la magnitud del peso es:

$W = 2\cdot (200\,lb)\cdot \sin 11.310^{\circ}$

$W \approx 78.447\,lbf$

En el Sistema Imperial, las fuerzas son medidas en forma gravitacional, entonces la magnitud de la fuerza gravitacional del peso equivale a la magnitud de su masa. En síntesis, la magnitud de la masa es $78.447\,lbm$ .

La magnitud de la masa del peso es 78.447 libras-masa.

7 0

3 years ago