Answer:
35.7 m
Explanation:
Let


We have to find the distance between Joe's and Karl'e tent.


Substitute the values then we get




Because vertical component of B lie in IV quadrant and y-inIV quadrant is negative.
By triangle addition of vector






Hence, the distance between Joe's and Karl's tent=35.7 m
Answer: The gravitational
Explanation: The student is pushing the box so u have to have gravitational force so it could move
Answer:
- 1.07 ft
Explanation:
V1 = (-5, 7, 2)
V2 = (3, 1, 2)
Projection of v1 along v2, we use the following formula
=\frac{\overrightarrow{V1}.\overrightarrow{V2}}{V2}
So, the dot product of V1 and V2 is = - 5 (3) + 7 (1) + 2 (2) = -15 + 7 + 4 = -4
The magnitude of vector V2 is given by
= 
So, the projection of V1 along V2 = - 4 / 3.74 = - 1.07 ft
Thus, the projection of V1 along V2 is - 1.07 ft.
so we need to find the direction of v2